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aivan3 [116]
3 years ago
6

Please help me. I will Mark whoever is first!!!

Mathematics
2 answers:
nata0808 [166]3 years ago
6 0

Answer:

750

Step-by-step explanation:

3000 divided by 4 =

750

Artyom0805 [142]3 years ago
6 0

Answer:

750 boxes

Step-by-step explanation:

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Step-by-step explanation:

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Consider the following hypothesis test: H 0: 20 H a: < 20 A sample of 50 provided a sample mean of 19.4. The population stand
goblinko [34]

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Step-by-step explanation:

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We need to find the test statistic value which is given by

z=\dfrac{\bar{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\\\\\\z=\dfrac{19.4-20}{\dfrac{2}{\sqrt{50}}}\\\\\\z=\dfrac{-0.6}{0.28}\\\\z=-2.14

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A statistics practitioner determined that the mean and stan-dard deviation of a data set were 90 and 15, respectively. What can
jasenka [17]

Answer:

If the distribution is bell shaped we can approximate the probability with high accuracy using the z score formula.

a) P(75

And for this case we can use the z score given by:

z = \frac{X-\mu}{\sigma}

And if we use it we got:

P(75

b) P(60

And for this case we can use the z score given by:

z = \frac{X-\mu}{\sigma}

And if we use it we got:

P(60

c) P(45

And for this case we can use the z score given by:

z = \frac{X-\mu}{\sigma}

And if we use it we got:

P(45

If the distribution is NOT bell shaped the approximation with the z score NOT works and we need to have the distribution for X in order to find the probabilities.

Step-by-step explanation:

Previous concepts

If the distribution is bell shaped we can approximate the probability with high accuracy using the z score formula.

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable of interest

We assume for this case that \mu=90 and \sigma=15

We are interested on this probability

P(75

And for this case we can use the z score given by:

z = \frac{X-\mu}{\sigma}

And if we use it we got:

P(75

Part b

P(60

And for this case we can use the z score given by:

z = \frac{X-\mu}{\sigma}

And if we use it we got:

P(60

Part c

P(45

And for this case we can use the z score given by:

z = \frac{X-\mu}{\sigma}

And if we use it we got:

P(45

If the distribution is NOT bell shaped the approximation with the z score NOT works and we need to have the distribution for X in order to find the probabilities.

5 0
3 years ago
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