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3 years ago

Help please, I'm stuck

Mathematics

2 answers:

mrs_skeptik [129]3 years ago

7 0

Answer:

Z<-3 is the anwser to this question, good luck !

Vikki [24]3 years ago

3 0

Multiply through by LCM, 4

$\frac{ - 3z - 1}{2} \times 4 > \: \: \: \frac{4}{1} \times 4$

$2( - 3z - 1) > 16$

$- 6z - 2 > 16$

$- 6z > 16 + 2$

$- 6z > 18$

$\frac{ - 6z}{ - 6} < \frac{18}{ - 6}$

$z < - 3$

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Use the Distributive Property to find (z−5)(z+3).

Anastasy [175]

Consider, $(z-5)(z+3)$ . Let's say $a = z-5$ then the problem reduces to $a(z+3)=za+3a$ . (Do you understand this step?)

So then replacing a again with our definition we get, $z(z-5)+3(z-5)=z^2-5z+3z-15=z^2-2z-15$ .

4 0

3 years ago

HELLOOOO HELP PLEASE

MA_775_DIABLO [31]

Answer:

$2*log(x)+log(y)$

Step-by-step explanation:

So, there are two logarithmic identities you're going to need to know.

Logarithm of a power:

$log_ba^c=c*log_ba$

So to provide a quick proof and intuition as to why this works, let's consider the following logarithm: $log_ba=x\implies b^x=a$

Now if we raise both sides to the power of c, we get the following equation: $(b^x)^c=a^c$

Using the exponential identity: $(x^a)^c=x^{a*c}$

We get the equation: $b^{xc}=a^c$

If we convert this back into logarithmic form we get: $log_ba^c=x*c$

Since x was the basic logarithm we started with, we substitute it back in, to get the equation: $log_ba^c=c*log_ba$

Now the second logarithmic property you need to know is

The Logarithm of a Product:

$log_b{ac}=log_ba+log_bc$

Now for a quick proof, let's just say: $x=log_ba\text{ and }y=log_bc$

Now rewriting them both in exponential form, we get the equations:

$b^x=a\\b^y=c$

We can multiply a * c, and since b^x = a, and b^y = c, we can substitute that in for a * c, to get the following equation:

$b^x*b^y=a*c$

Using the exponential identity: $x^{a}*x^b=x^{a+b}$ , we can rewrite the equation as:

$b^{x+y}=ac$

taking the logarithm of both sides, we get:

$log_bac=x+y$

Since x and y are just the logarithms we started with, we can substitute them back in to get: $log_bac=log_ba+log_bc$

Now let's use these identities to rewrite the equation you gave

$log(x^2y)$

As you can see, this is a log of products, so we can separate it into two logarithms (with the same base)

$log(x^2)+log(y)$

Now using the logarithm of a power to rewrite the log(x^2) we get:

$2*log(x)+log(y)$

3 0

2 years ago

Can anyone give me a geometric sequence will give brainlinest and need sequence of 6

snow_lady [41]

Answer:

3, 6, 9, 12, 15, 18

Step-by-step explanation:

If you count by threes you can make a Geometric Sequence of 6.

Final answer: 3, 6, 9, 12, 15, 18.

3 0

3 years ago

The radius of a circle is 6 inches. What is the circle's circumference? Use 3.14 for .

Vikentia [17]

Answer:

37.68 inches

Step-by-step explanation:

The equation for the circumference of the circle is:

$C=2\pi r$

We can substitute 6 in for "r" and 3.14 for "π":

$C=2(3.14)(6\ in)\\C=12\ in(3.14)\\C=37.68\ in^$

4 0

2 years ago

It’s number 9 I think it’s 5 or 15 IDK plz tell me the answer to A and B plz

Oduvanchick [21]

Answer:

you have it right its 29 and 5

Step-by-step explanation:

8 0

3 years ago

Help please, I'm stuck ​

Help please, I'm stuck