Step 1: Simplify both sides of the equation.
3
x
+
2
=
−
13
Step 2: Subtract 2 from both sides.
3
x
+
2
−
2
=
−
13
−
2
3
x
=
−
15
Step 3: Divide both sides by 3.
3
x
3
=
−
15
3
x
=
−
5
Given:
The data values are
11, 12, 10, 7, 9, 18
To find:
The median, lowest value, greatest value, lower quartile, upper quartile, interquartile range.
Solution:
We have,
11, 12, 10, 7, 9, 18
Arrange the data values in ascending order.
7, 9, 10, 11, 12, 18
Divide the data in two equal parts.
(7, 9, 10), (11, 12, 18)
Divide each parenthesis in 2 equal parts.
(7), 9, (10), (11), 12, (18)
Now,
Median = 
=
=
Lowest value = 7
Greatest value = 18
Lower quartile = 9
Upper quartile = 12
Interquartile range (IQR) = Upper quartile - Lower quartile
= 12 - 9
= 3
Therefore, median is 10.5, lowest value is 7, greatest value is 18, lower quartile 9, upper quartile 12 and interquartile range is 3.
A secant is simply a line that intersects the circle at exactly two points.
Therefore, line GH is a secant of circle
B since it intersects the circle ast 2 points.
Answer:
12
Step-by-step explanation:
1/2 ton would be the correct answer since a single ton is 2,000 lbs