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3 years ago

11

What is the area of the trapezoid? A trapezoid has a base of 12 centimeters, a height of 16 centimeters, and a top side length o

f 10 centimeters.

2 answers:

exis [7]3 years ago

5 0

16 +160 so 176 because two triangles put together to make 16 and then just 16 x 10

Oliga [24]3 years ago

5 0

Answer:

on edge its ur cool

Step-by-step explanation:

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Mariah went to the store to buy a coat. The coat originally cost $120.00. Mariah used a coupon

creativ13 [48]

Answer: $24

Step-by-step explanation:

Mariano saved $24because

120 x 0.2=24

She payed $96

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3 years ago

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Given that (-3 3) is on the graph of f(x) find the corresponding point for the function f(x+1)

vredina [299]

Answer:

(-3, 4).

Step-by-step explanation:

When f(x) becomes f(x + 1), all that is happening is that the y-value increases by 1.

So, (-3, 3) becomes (-3, 3 + 1). That is (-3, 4).

Hope this helps!

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4 years ago

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What number comes next in this pattern? 46, 49, 52, 55, 58,...

Ksenya-84 [330]

Answer:

61

Step-by-step explanation:

just add 3 to the next one

8 0

3 years ago

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Gabe drops a hammer from an apartment that is 30 meters above the ground. The height of the hammer in meters, h, after t seconds

anyanavicka [17]

Simplifying
h(t) = -1t2 + -2t + 30

Multiply h * t
ht = -1t2 + -2t + 30

Reorder the terms:
ht = 30 + -2t + -1t2

Solving
ht = 30 + -2t + -1t2

Solving for variable 'h'.

Move all terms containing h to the left, all other terms to the right.

Divide each side by 't'.
h = 30t-1 + -2 + -1t

Simplifying
h = 30t-1 + -2 + -1t

Reorder the terms:
h = -2 + 30t-1 + -1t

4 0

3 years ago

In a nursery class of 18 pupils, the average is 4<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20" id="TexFormula1"

Alisiya [41]

Answer:

The sum of ages of all 18 pupils in the class = 81

Step-by-step explanation:

Total number of pupil in the class = 18

Average of years in the class = $4\frac{1}{2}$

Now, $4\frac{1}{2} = 4 + \frac{1}{2} = 4 + 0.5 = 4.5$

⇒Average of sum of ages in the class = 4.05

Let us assume the sum of ages of all students in the class = m

By the formula for AVERAGE:

$\textrm{Average of n obseravtions} = \frac{\textrm{Sum of n observations}}{\textrm{n}}$

$\implies 4.5 = \frac{m}{18}$

or, m = 18 x 4.5 = 81

Hence, the sum of ages of all 18 pupils in the class = 81

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3 years ago

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