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MakcuM [25]
3 years ago
11

Factor 200t+8t^3-80t^2

Mathematics
2 answers:
valina [46]3 years ago
6 0

Answer:

8t(t - 5)^2

Step-by-step explanation:

I would immediately rearrange these terms in descending order by powers of t:

8t^3 - 80t^2 + 200t

Then I'd factor out 8t:

8t(t^2 - 10 t + 25).

Finally, I'd factor the quadratic t^2 - 10 t + 25:

(t - 5)^2

and so 200t+8t^3-80t^2 in factored form is 8t(t - 5)^2.

Bad White [126]3 years ago
6 0

Answer:

Step-by-step explanation:

It would be better to list the terms in descending order.

8t^3 - 80t^2 + 200t                  Take out a common factor of t

t(8t^2 - 80t + 200)                    Now take out 8

8t (t^2 - 10t + 25)                      Now factor the polynomial

8t(t - 5)(t - 5)

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Answer:

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Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

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Answer:

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Step-by-step explanation:

We have been given that for a normal distribution with μ=500 and σ=100. We are asked to find the minimum score that is necessary to be in the top 60% of the distribution.

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