<u>The solution is (1,2)</u>
Step-by-step explanation:
7x + 10y = 27
x - 10y = -19 +--------------------
8x = 8
Divide by 8 on both sides
x = 1
To find y substitute any of the equations to 1
7(1) + 10y = 27
7 + 10y = 27
Substract 7 from both sides
10y = 20
Divide by 10
y = 2
X equals 38. That means, angle R is 38, angle P is 69, and angle Q is 73.
You get x=38 by doing x+35+x+2x-7 = 180
*Hope this helps!*
Answer:

Step-by-step explanation:
Arithmetic sequence:

Here a is the first term and d is the common difference.
⇒
------------(I)
⇒ a + 19d = 100 ---------(II)
Subtract equation (I) from (II)
(I1) a + 19d = 100
(II) a + 13d = 46
<u>- - -</u>
6d = 54
d = 54 ÷ 6

Substitute d = 9 in equation(I) and find 'a',
a + 13*9= 46
a + 117 = 46
a = 46 - 117
a = -71

= -71 + 18
= -53

= -71 + 54
= -17

= -71 + 9*n - 1 *9
= -71 + 9n - 9
= -71 - 9 + 9n
= - 80 + 9n
Answer:
Hello !
The solutions are: -8 , -4 , 6
Hope this helps !
So if you find the 1st term, you should write 1 instead of n
T1 = 6.1 -1
T1= 6-1
T1= 5
Hope it helps!
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