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2 years ago

Need help with this problem

Mathematics

1 answer:

bearhunter [10]2 years ago

4 0

Answer:

C. -1/2

Step-by-step explanation:

well the formula for slope is m=(y2-y1/x2-x1). y2 = -5 y1= 3 x2 = 2 x1 = -14. put that all together to get -5-3/2-(-14). well -5 - 3 = -8. the second one is like a multiplication problem so a negative minus a negative is a positive. which give u 2 + 14 = 16. so you get the fraction -8/16 both are divisible by 8 so divide the equation by 8 and you get -1/2.

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Daniel dives into a swimming pool. The height of his head is represented by the function h(t) = -8t2 - 28t + 60, where t is the

8_murik_8 [283]

So, h(t) is how far is Daniel's head from the surface of the water, namely the surface itself is when the height is nill, so his head is at the surface and the height of it is just 0, thus h(t) = 0. Namely, what is "t" when h(t) is 0?

$\bf h(t)=-8t^2-28t+60\implies \stackrel{h(t)}{0}=-8t^2-28t+60
\\\\\\
0=-2t^2-7t+15\implies 2t^2+7t-15=0\implies (2t+3)(t-5)=0
\\\\\\
\begin{cases}
2t+3=0\implies 2t=-3\implies &t=-\frac{3}{2}\\\\
t-5=0\implies &\boxed{t=5}
\end{cases}$

clearly the seconds cannot be a negative unit, so is not -3/2.

6 0

2 years ago

The U.S.A. Olympic Synchronized Swimming Team is designing a routine for their upcoming competition. From the center of the pool

Mama L [17]

Answer:

The equation of the circle is;

(x - 2)² + (y - 4)² = 5²

Step-by-step explanation:

We note that the general equation of a circle is given as follows;

(x - h)² + (y - k)² = r²

Where;

(h, k) = The coordinates of the center of the circle

r = The radius of the circle

The given parameters are;

The location of the center of the pool to the center of their formation = 2 feet to the right and 4 feet up from the center of the pool

The point through which the circle which they form goes through = A point 3 feet to the left and 4 feet up from the center of their formation

Taking the center of the pool as the origin of the coordinate plane system, we have;

The coordinate of the center of the circle = The coordinate of their motion from the center of the circle

∴ The coordinate of the center of the circle = (2, 4)

∴ (h, k) = (2, 4)

h = 2, k = 4

The coordinate of the point through which the circle passes = (2 - 3, 4 + 4) = (-1, 8)

∴ The length of the radius, 'r', can be found as, r = √((-3)² + 4²) = 5 or r = √((-1 - 2)² + (8 - 4)²) = 5

r = 5

The equation of the circle is therefore presented by substituting the values of 'h', 'k', and 'r', as follows;

(x - 2)² + (y - 4)² = 5².

4 0

2 years ago

Please help me!! im so close to finshing

gtnhenbr [62]

Answer:

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Step-by-step explanation:

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2 years ago

The diagonals of a rhombus are 10 inches and 24 inches. What is the perimeter of the rhombus, in inches?

umka2103 [35]

Make this brainliest please, and thank you

Answer:

P<em>=52in is ya answer!</em>

3 0

2 years ago

Calculamos el volumen (V) de un prisma cuadrangular expresado en unidades cúbicas. Respondemos: ¿cómo se calcula?...............

Vadim26 [7]

Answer:

a) El procedimiento queda resumido en lo que sigue:

1) Se halla el área de la base del cuadrilátero.

2) Se multiplica el resultado anterior por la longitud del prisma.

b) La expresión para calcular el volumen del prisma ( $V$ ), en unidades cúbicas, es:

$V = w\cdot h \cdot l$

Donde:

$w$ - Ancho de la base, en unidades.

$h$ - Altura de la base, en unidades.

$l$ - Longitud del prisma, en unidades.

Step-by-step explanation:

a) Dimensionalmente hablando, la unidad de volumen es igual al cubo de la unidad de longitud. Se explica a continuación los pasos necesarios para el cálculo de prisma cuadrangular:

1) Se halla el área de la base del cuadrilátero.

2) Se multiplica el resultado anterior por la longitud del prisma.

b) En consecuencia, se deriva la expresión para el volumen del prisma:

$V = A\cdot l$ (1)

Donde:

$A$ - Área de la base del prisma, en unidades cuadradas.

$l$ - Longitud del prisma, en unidades.

$V = w\cdot h \cdot l$ (2)

Donde:

$w$ - Ancho de la base, en unidades.

$h$ - Altura de la base, en unidades.

5 0

2 years ago

Need help with this problem​

Need help with this problem