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Lubov Fominskaja [6]
3 years ago
11

Find the diameter of the circular garden whose circumference is 124.03 cm​

Mathematics
1 answer:
leonid [27]3 years ago
6 0

Answer:

\color{magenta} \huge{ \boxed{answer}}

<h3>Solve for diameter</h3>

<h2><u>d</u><u> </u><u>=</u><u> </u><u>3</u><u>9</u><u>.</u><u>4</u><u>8</u></h2>

<u>h</u><u>o</u><u>p</u><u>e</u><u>f</u><u>u</u><u>l</u><u>l</u><u>y</u><u> </u><u>h</u><u>e</u><u>l</u><u>p</u><u>:</u><u>)</u>

Step-by-step explanation:

✨use <u>#</u><u>C</u><u>a</u><u>r</u><u>r</u><u>y</u><u>O</u><u>n</u><u>L</u><u>e</u><u>a</u><u>r</u><u>n</u><u>i</u><u>n</u><u>g</u> to help our medical frontliners✨

<h2><em><u>#</u></em><em><u>C</u></em><em><u>a</u></em><em><u>r</u></em><em><u>r</u></em><em><u>y</u></em><em><u>O</u></em><em><u>n</u></em><em><u>L</u></em><em><u>e</u></em><em><u>a</u></em><em><u>r</u></em><em><u>n</u></em><em><u>i</u></em><em><u>n</u></em><em><u>g</u></em></h2>

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(x + 6)(x + 2) = 60?
Salsk061 [2.6K]

Answer:

x^3=6

Step-by-step explanation:

x(x+2)+6(x+2)=60

x^2+2x +6x +12=60

5 0
3 years ago
A monomial of degree 7 and a leading coefficient of -3
OleMash [197]

Answer:

no clue

Step-by-step explanation:

8 0
3 years ago
Which of the following sets are subspaces of R3 ?
Ratling [72]

Answer:

The following are the solution to the given points:

Step-by-step explanation:

for point A:

\to A={(x,y,z)|3x+8y-5z=2} \\\\\to  for(x_1, y_1, z_1),(x_2, y_2, z_2) \varepsilon A\\\\ a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)

                                        =3(aX_l +bX_2) + 8(ay_1 + by_2) — 5(az_1+bz_2)\\\\=a(3X_l+8y_1- 5z_1)+b (3X_2+8y_2—5z_2)\\\\=2(a+b)

The set A is not part of the subspace R^3

for point B:

\to B={(x,y,z)|-4x-9y+7z=0}\\\\\to for(x_1,y_1,z_1),(x_2, y_2, z_2) \varepsilon  B \\\\\to a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)

                                             =-4(aX_l +bX_2) -9(ay_1 + by_2) +7(az_1+bz_2)\\\\=a(-4X_l-9y_1+7z_1)+b (-4X_2-9y_2+7z_2)\\\\=0

\to a(x_1,y_1,z_1)+b(x_2, y_2, z_2) \varepsilon  B

The set B is part of the subspace R^3

for point C: \to C={(x,y,z)|x

In this, the scalar multiplication can't behold

\to for (-2,-1,2) \varepsilon  C

\to -1(-2,-1,2)= (2,1,-1) ∉ C

this inequality is not hold

The set C is not a part of the subspace R^3

for point D:

\to D={(-4,y,z)|\ y,\ z \ arbitrary \ numbers)

The scalar multiplication s is not to hold

\to for (-4, 1,2)\varepsilon  D\\\\\to  -1(-4,1,2) = (4,-1,-2) ∉ D

this is an inequality, which is not hold

The set D is not part of the subspace R^3

For point E:

\to E= {(x,0,0)}|x \ is \ arbitrary) \\\\\to for (x_1,0 ,0) ,(x_{2},0 ,0) \varepsilon E \\\\\to  a(x_1,0,0) +b(x_{2},0,0)= (ax_1+bx_2,0,0)\\

The  x_1, x_2 is the arbitrary, in which ax_1+bx_2is arbitrary  

\to a(x_1,0,0)+b(x_2,0,0) \varepsilon  E

The set E is the part of the subspace R^3

For point F:

\to F= {(-2x,-3x,-8x)}|x \ is \ arbitrary) \\\\\to for (-2x_1,-3x_1,-8x_1),(-2x_2,-3x_2,-8x_2)\varepsilon  F \\\\\to  a(-2x_1,-3x_1,-8x_1) +b(-2x_1,-3x_1,-8x_1)= (-2(ax_1+bx_2),-3(ax_1+bx_2),-8(ax_1+bx_2))

The x_1, x_2 arbitrary so, they have ax_1+bx_2 as the arbitrary \to a(-2x_1,-3x_1,-8x_1)+b(-2x_2,-3x_2,-8x_2) \varepsilon F

The set F is the subspace of R^3

5 0
3 years ago
Suppose that you earned a​ bachelor's degree and now​ you're teaching high school. The school district offers teachers the oppor
stepan [7]

Answer:

Step-by-step explanation:

Answer:

a. The amount that is saved at the expiration of the 5 year period is $22,769.20¢

b. The amount of interest is $2,769.20¢

Step-by-step explanation:

Since the amount that is deposited every year for a period of five years is $4,000 and the rate of the interest is 6.5%. We can always calculate the amount that is saved at the expiration of the five years.

    We will first state the formula for calculating the future value of annuity:-

      Future value of annuity =

                      P[\frac{(1 + r)^{t}-1 }{r}]

   Where P is the amount deposited per year.

   r is the rate of interest

   t is the time or period

 

    and in this case, the actual value of P = $4,000

      rate of interest, r is 6.5% = 0.065

      time, t is 5 years.

   Substituting e, we have:

   Fv of annuity =

                          4,000[\frac{(1 + 0.065)^{5}-1 }{0.065 }]

   = 4,000 × [((1.065)^5)- 1/0.065]

 = 4,000 × [(1.37 - 1)/0.065]

 = 4,000 × (0.37/0.065)

 = 4,000 × 5.6923

 = $22,769.20¢

a. Therefore the amount that is saved at the end of the five (5) years is $22,769.20¢

b. To find the interest, we will calculate the amount of deposit made during the period of five years and subtract the sum from the current amount that is saved ($22,769.29¢).

  Since I deposited 4,000 every year for five years, the total amount of deposit I made at the period =

       4,000 × 5 = $20,000

  The amount of interest is then = $22,769.20¢ - $20,000 = $2,769.20¢

3 0
3 years ago
Which triangle is similar to triangle T
Alex17521 [72]

Answer:

2nd one from the left.

Step-by-step explanation:

it has the same angle measures.

3 0
3 years ago
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