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vovikov84 [41]
3 years ago
14

WORTH 40 POINTS

Mathematics
1 answer:
djverab [1.8K]3 years ago
7 0

Answer:

Step-by-step explanation:

In this section, we will focus on graphing hyperbolas that open left and right or ... To easily sketch the asymptotes we make use of two special line segments ... From the center (5,4), mark points 3 units left and right as well as 2 units up and down. ... standard form for the equation of a hyperbola given the following information.

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< when graphing this is ineqality sign, the following apply.A open Dot, arrow to the right. B.close dot,arrow to the left.C.
8_murik_8 [283]

Answer:

C

Step-by-step explanation:

A open dot indicates that the number it is placed on cannot be part of the solution, it's always paired with > or <, and < means less than, meaning the arrow would point left

4 0
4 years ago
Pls HELPPPP!!!!!!!!!!
murzikaleks [220]

<em>Hey</em><em>!</em><em>!</em><em>!</em>

<em>her</em><em>e's</em><em> </em><em>your</em><em> </em><em>answer</em>

<em>Area</em><em> </em><em>of</em><em> </em><em>rectangular</em><em> </em><em>field</em><em>=</em><em>L</em><em>*</em><em>B</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>9</em><em>/</em><em>1</em><em>0</em><em>*</em><em>1</em><em>/</em><em>2</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>9</em><em>/</em><em>2</em><em>0</em><em> </em><em>square</em><em> </em><em>mile</em>

<em>So</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>of</em><em> </em><em>option</em><em> </em><em>A</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>

6 0
4 years ago
Read 2 more answers
Taylor graphs the system below on her graphing calculator and decides that f(x)=g(x) at x=0, x=1, and x=3. Provide Taylor some f
goblinko [34]

Answer:

f(x)=g(x) at x= 0 and x= 1 and not at x= 3.

Step-by-step explanation:

We have the functions, f(x)=2x+1 and g(x)=2x^2+1.

It is given that,

At x=0, x=1, and x=3, f(x)=g(x)

i.e. 2x+1=2x^2+1

i.e. 2x^2-2x=0

i.e. 2x(x-1)=0

i.e. x= 0 and (x-1)= 0

i.e. x= 0 and x= 1.

Also, after plotting the graphs of both the functions, we see their intersection point are (0,1) and (1,3).

Thus, we get that f(x)=g(x) at x= 0 and x= 1 and not at x= 3.

5 0
3 years ago
Two trains leave the same station at the same time, but are headed in opposite directions. One train travels at 70 mph and the o
Umnica [9.8K]
70t + 80t = 600
150t = 600 Simplify
t = 4 Divide
70(4) + 80(4) = 600 Check

4 hours
7 0
3 years ago
Answer please I’m dying from math
charle [14.2K]

Answer:

\huge\boxed{\text{D)} \  15x^4 + 2x^3 - 8x^2 - 22x - 15}

Step-by-step explanation:

We can solve this multiplication of polynomials by understanding how to multiply these large terms.

To multiply two polynomials together, we must multiply each term by each term in the other polynomial. Each term should be multiplied by another one until it's multiplied by all of the terms in the other expression.

  • <em>We can do this by focusing on one term in the first polynomial and multiplying it by </em><em>all the terms</em><em> in the second polynomial. We'd then repeat this for the remaining terms in the second polynomial.</em>

Let's first start by multiplying the first term of the first polynomial, 3x^2, by all of the terms in the second polynomial. (5x^2+4x+5)

  • 3x^2 \cdot  5x^2 = 15x^4
  • 3x^2 \cdot 4x = 12x^3
  • 3x^2 \cdot 5 = 15x^2

Now, we can add up all these expressions to get the first part of our polynomial. Ordering by exponent, our expression is now

  • \displaystyle 15x^4 + 12x^3 + 15x^2

Now let's do the same with the second term (-2x) and the third term (-3).

  • -2x \cdot 5x^2 = -10x^3  
  • -2x \cdot 4x = -8x^2
  • -2x \cdot 5 = -10x
  • Adding on to our original expression: \displaystyle 15x^4 + 12x^3 - 10x^3 + 15x^2 - 8x^2 - 10x

  • -3 \cdot 5x^2 = -15x^2
  • -3 \cdot 4x = -12x
  • -3 \cdot 5 = -15
  • Adding on to our original expression: \displaystyle 15x^4 + 12x^3 - 10x^3 + 15x^2 - 8x^2 - 15x^2 - 10x - 12x - 15

Phew, that's one big polynomial! We can simplify it by combining like terms. We can combine terms that share the same exponent and combine them via their coefficients.

  • 12x^3 - 10x^3 = 2x^3
  • 15x^2 - 8x^2 - 15x^2 = -8x^2
  • -10x - 12x = -22x

This simplifies our expression down to 15x^4 + 2x^3 - 8x^2 - 22x - 15.

Hope this helped!

7 0
3 years ago
Read 2 more answers
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