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3 years ago

Stick a pencil down my licorice

Mathematics

1 answer:

Masteriza [31]3 years ago

8 0

What????????????
Don't post unless you really need help

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. CDEF is a trapezium

guajiro [1.7K]

9514 1404 393

Answer:

24 cm²

Step-by-step explanation:

To find the area of the trapezium, we must know the length CD. That means we must know the length BC. Fortunately, the perimeter of ABCF is given, so we have ...

P = 2(AB +BC)

BC = (P/2) -AB = (20 cm)/2 - 6 cm = 4 cm

Then CD is ...

CD = BD -BC = 9 cm -4 cm = 5 cm

The area of the trapezium is given by the formula ...

A = (1/2)(b1 +b2)h

A = (1/2)(5 cm + 3 cm)(6 cm) = 24 cm²

The area of trapezium CDEF is 24 cm².

3 0

2 years ago

Whats 1 + 1 = ? I don't know? But if you answer you will be brainiest and get 100 points free!

Arada [10]

2 is your answer lol

8 0

3 years ago

Read 2 more answers

What does the shaded part represent in the given Venn -diagram

Snezhnost [94]

Pls look at your question before asking a question. You didn’t give us a venn diagram to look at.

Brainliest?

5 0

2 years ago

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Suppose △ ITH ≅ △ APG

sineoko [7]

To figure this question out, I recommend the FOIL method.

F: First
O: Outer
I: Inner
L: Last

Statement A is true. IH and AG in the FOIL method is the Outer.

4 0

2 years ago

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For the following demand equation compute the elasticity of demand and determine whether the demand is elastic, unitary, or inel

adelina 88 [10]

Answer:

Demand is inelastic at p = 9 and therefore revenue will increase with

an increase in price.

Step-by-step explanation:

Given a demand function that gives q in terms of p, the elasticity of demand is

$E=|\frac{p}{q}\cdot \frac{dq}{dp} |$

If E < 1, we say demand is inelastic. In this case, raising prices increases revenue.
If E > 1, we say demand is elastic. In this case, raising prices decreases revenue.
If E = 1, we say demand is unitary.

We have the following demand equation $D(p)=-\frac{3}{4}p+29$ ; p = 9

Applying the above definition of elasticity of demand we get:

$E(p)=\frac{p}{q}\cdot \frac{dq}{dp}$

where

p = 9
q = $-\frac{3}{4}p+29$
$\frac{dq}{dp}=\frac{d}{dp}(-\frac{3}{4}p+29)$

$\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{d}{dp}\left(\frac{3}{4}p\right)+\frac{d}{dp}\left(29\right)\\\\\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{3}{4}$

Substituting the values

$E(9)=\frac{9}{-\frac{3}{4}(9)+29}\cdot -\frac{3}{4}\\\\E(9)=\frac{36}{89}\cdot -\frac{3}{4}\\\\E(9)=-\frac{27}{89}\approx -0.30337$

$|E(9)|=|\frac{27}{89}| < 1$

Demand is inelastic at p = 9 and therefore revenue will increase with an increase in price.

6 0

2 years ago