Two consecutive odd integers with a sum of 36 are 17 and 19.
To find these integers, we start by using the definition of consecutive odd integers to represent our consecutive odd integers as n and n + 2. Now, we can set up an equation using the fact that the sum of these two integers is equal to 36.
n + (n + 2) = 36
Solving this equation for n will give us the first of our consecutive odd integers that sum to 36.
n + (n + 2) = 36
Simplify the left-hand side.
2n + 2 = 36
Subtract 2 from both sides of the equation.
2n = 34
Divide both sides of the equation by 2.
n = 17
We get that the first of the two consecutive odd integers is 17, so the second one is 17 + 2, or 19. Therefore, we find that two consecutive odd integers whose sum is 36 are 17 and 19.h
THE MAGIC OF COPY AND PASTE *bows*
Answer:
4 2/3
Step-by-step explanation:
(m-4) (3m-2)=0
Use the zero product property to find the zeros
m-4 = 0 3m-2 =0
m =4 3m =2
m = 2/3
We want the sum of the zero's
4+ 2/3
4 2/3
Answer:
Did u find the answer
Step-by-step explanation:
8,-2. place the x as 8 and y as -2.
