Answer:
D. 4
Step-by-step explanation:
![[(p^2) (q^{-3}) ]^{-2}.[(p)^{-3}(q)^5] ^{-2}\\\\=[(p^2) (q^{-3}) \times(p)^{-3}(q)^5 ]^{-2}\\\\=[(p^{2}) \times(p)^{-3} \times (q^{-3}) \times(q)^5 ]^{-2}\\\\=[(p^{2-3}) \times (q^{5-3}) ]^{-2}\\\\=[(p^{-1}) \times (q^{2}) ]^{-2}\\\\=(p^{-1\times (-2)}) \times (q^{2\times (-2) }) \\\\=p^{2}\times q^{-4} \\\\= \frac{p^2}{q^4}\\\\= \frac{(-2)^2}{(-1)^4}\\\\= \frac{4}{1}\\\\= 4](https://tex.z-dn.net/?f=%20%5B%28p%5E2%29%20%28q%5E%7B-3%7D%29%20%5D%5E%7B-2%7D.%5B%28p%29%5E%7B-3%7D%28q%29%5E5%5D%20%5E%7B-2%7D%5C%5C%5C%5C%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3D%5B%28p%5E2%29%20%28q%5E%7B-3%7D%29%20%5Ctimes%28p%29%5E%7B-3%7D%28q%29%5E5%20%5D%5E%7B-2%7D%5C%5C%5C%5C%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3D%5B%28p%5E%7B2%7D%29%20%5Ctimes%28p%29%5E%7B-3%7D%20%5Ctimes%20%28q%5E%7B-3%7D%29%20%5Ctimes%28q%29%5E5%20%5D%5E%7B-2%7D%5C%5C%5C%5C%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3D%5B%28p%5E%7B2-3%7D%29%20%5Ctimes%20%28q%5E%7B5-3%7D%29%20%5D%5E%7B-2%7D%5C%5C%5C%5C%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3D%5B%28p%5E%7B-1%7D%29%20%5Ctimes%20%28q%5E%7B2%7D%29%20%5D%5E%7B-2%7D%5C%5C%5C%5C%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3D%28p%5E%7B-1%5Ctimes%20%28-2%29%7D%29%20%5Ctimes%20%28q%5E%7B2%5Ctimes%20%28-2%29%20%7D%29%20%5C%5C%5C%5C%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3Dp%5E%7B2%7D%5Ctimes%20q%5E%7B-4%7D%20%5C%5C%5C%5C%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3D%20%5Cfrac%7Bp%5E2%7D%7Bq%5E4%7D%5C%5C%5C%5C%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3D%20%5Cfrac%7B%28-2%29%5E2%7D%7B%28-1%29%5E4%7D%5C%5C%5C%5C%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3D%20%5Cfrac%7B4%7D%7B1%7D%5C%5C%5C%5C%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3D%204)
Well this only simplifies to a smaller equation
so the answer would be...
2a²-9b²
For the first letter we have 24 choices. Since letters can't repeat the second letter has 23 choices (24 minus 1 that was used for the first slot) and the third has 22 (24 minus one for the first slot and one for the second slot).
The total number of combinations is thus: 24 x 23 x 22= 12,144
Answer:
I dont know the answer but I'm just doing this for the answer
I see beauty in everything but me