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3 years ago

What is the sum of the zeros of the equation (m-4) (3m-2)=0 ? Enter your answer as a fraction.

Mathematics

1 answer:

Katen [24]3 years ago

6 0

Answer:

4 2/3

Step-by-step explanation:

(m-4) (3m-2)=0

Use the zero product property to find the zeros

m-4 = 0 3m-2 =0

m =4 3m =2

m = 2/3

We want the sum of the zero's

4+ 2/3

4 2/3

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1 year ago

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2 years ago

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Let "n" be the number of nickels

Let "d" be the number of dimes

We know that,

value of 1 nickel = $ 0.05

value of 1 dime = $ 0.10

<em><u>Given that There are three more than twice as many nickels as there are dimes</u></em>

Number of nickels = 3 + 2(number of dimes)

n = 3 + 2d ---- eqn 1

<em><u>Also given that coin bank that excepts only nickels and dimes contains $9.15</u></em>

number of nickels x value of 1 nickel + number of dimes x value of 1 dime = 9.15

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0.05n + 0.10d = 9.15 ---- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Substitute eqn 1 in eqn 2

0.05(3 + 2d) + 0.10d = 9.15

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From eqn 1

n = 3 + 2(45)

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