Answer:
a / (a - 4) = a(a + 4) / ((a - 4)(a + 4)) = (a^2 + 4a) / (a^2 - 16) = -(a^2 + 4a) / (16 - a^2)
Answer:
It's 4x - 8 + 4y
Step-by-step explanation:
4(x-2+y)
4 (x) = 4x
4 (2) = 8
4 (y) = 4y
4x - 8 + 4y
Answer: 72 u^2
<h3>
Explanation:</h3>
What we know:
- Both triangles are identical
- Both rectangles are different
- There are values in units^2 given
- There are right angles
How to solve:
We need to find the area of at least one of the triangles and double it. Then, we need to find the areas of both rectangles. Finally, we need to add these areas to find the total area. The final area will be represented in units squared (u^2)
<h2>
Process:</h2>
Triangles
Set up equation A = 1/2(bh)
Substitute A = 1/2(4*3)
Simplify A = 1/2(12)
Solve A = 6
Double *2
A = 12 u^2
Rectangles
Set up equation A = lh
Substitute A = (14)(3)
Simplify A = 42 u^2
Set up equation A = lh
Substitute A = [14-(4+4)](3)
Simplify A = (14-8)(3)
Simplify A = (6)(3)
Multiply A = 18 u^2
Total Area
Set up equation A = R1+R2+T
Substitute A = 42 + 18 + 12
Simplify A = 60 + 12
Solve A = 72 u^2
<h3>
Answer: 72 u^2</h3>
1.) Multiply the parentheses by -5x
2.) Move the constant to the left
3.) Change the signs
4.) Solve the quadratic equation
5.) Evaluate the powers and multiply
6.) Calculate
Answer: No solution
Answer:
x = 3, y = 4 and z = -5.
Step-by-step explanation:
Use the elimination method:
-3x + 2y + z = -6...........(1)
x + 3y + 2z = 5..............(2)
4x + 4y + 3z = 13..........(3)
Multiply the first equation by -2:
6x - 4y - 2z = 12 Add this to equation (2):
7x - y = 17...........(4)
Now Multiply equation (2) by 3 and equation (3) by -2
3x + 9y + 6z = 15 ............(5)
-8x - 8y - 6z = -26............(6) Adding (5) + (6):
-5x + y = -11..........(7)
Now Add (7) and (4):
2x = 6
x = 3.
Now substitute for x in (4):
7(3) - y = 17
-y = 17 - 21 = -4
y = 4.
Finally substitute for x and y in equation (3) to find z:
4(3) + 4(4) +3z = 13
3z = 13 - 12 - 16 = -15
z = -5.
