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3 years ago

Bring the fraction a/a-4 to a denominator of 16-a^2

Mathematics

1 answer:

Dmitry_Shevchenko [17]3 years ago

3 0

Answer:

a / (a - 4) = a(a + 4) / ((a - 4)(a + 4)) = (a^2 + 4a) / (a^2 - 16) = -(a^2 + 4a) / (16 - a^2)

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Connor borrows $8,000 at a rate of 19% interest per year. What is the amount due at the end of 7 years if the interest is compou

Vlada [557]

Answer:

Step-by-step explanation:

30,248.35

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9 months ago

Kameryn flips a coin, rolls a 6-sided die, and then spins an 8-section

Levart [38]

Answer:

96 possible outcomes

Step-by-step explanation:

2 x 6 x 8 = 96

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3 years ago

The manager of a snack bar buys bottled water in packs of 35 and candy bars in packs of 20. Then, she sells the items individual

Lerok [7]

$\Huge\bf{\underline{\red \dag { Aиѕωєя }}} \red \dag$

4 Packs of water and 7 Packs of candy bars.

So, we wanna know the smallest number that both 35 and 20 will go into.

Find the Least Common Multiple (LCM), but to find the LCM we need to find the prime factorization of each of the following number :-

$\sf {35 = 5(7)}$

$\sf \red {20 = 5(4)}$

$\sf {4 = 2(2)}$

$\sf \red {20 = 5(2)(2)$

~Now multiply all the numbers by 5 :-

$\sf \pink{5(7)(2)(2) = 35(2)(2) = 70(2) = 140}$

This means she needs 140 bottles of water and 140 candybars.

Water is sold in packs of 35, this means that she needs :

$\sf \orange{ \frac{140}{35} = 4\: packs \: of \: water}$

Candy bars are sold in packs of 20, this means she needs :

$\sf \green{ \frac{140}{20} = 7 \: packs \: of \: candy \: bars}$

6 0

2 years ago

Find the distance between E(-3,4) and B(-1,6)

Marrrta [24]

Answer:

The answer is

<h2> $2 \sqrt{2 } \: \: or \: \: 2.828 \: \: \: units$ </h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

E(-3,4) and B(-1,6)

The distance between them is

We have the final answer as

<h3> $2 \sqrt{2 } \: \: or \: \: 2.828 \: \: \: units$ </h3>

Hope this helps you

4 0

2 years ago

n a call center the number of received calls in a day can be modeledby a Poisson random variable. We know that, on average, 0.5%

guapka [62]

Answer:Pois(ln(200))

Step-byy-step explanation:

Let N be the number of received calls in a day

That is

N∼Pois(λ).

0.5% = 0.5/100 = 1/200 of no calls

P(N=0)=e^−λ=1/200

-λ=e^(1/200)

λ=in(200)

Our number of calls in a day is distributed Pois(ln(200)).

7 0

3 years ago

Read 2 more answers