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Nataly_w [17]
3 years ago
8

Give the dregree for the polynomial

Mathematics
1 answer:
Novay_Z [31]3 years ago
5 0

Answer:

In the case of a polynomial with more than one variable, the degree is found by looking at each monomial within the polynomial, adding together all the exponents within a monomial, and choosing the largest sum of exponents.

Step-by-step explanation:

That sum is the degree of the polynomial.

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<h2>A thank you note </h2>

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2 years ago
Line K has the equation 9x-4y=-5x4.
Yuki888 [10]

Answer:

y = (9/4)x + 2, given that I've assume the correct meaning of "-5x4."

Step-by-step explanation:

A parallel line has the same slope as the reference line,

The reference line is 9x-4y = -5x4, as written.  I'm not sure the 4 belongs, but I'll assume it is written correctly.  I'm not sure if the term -5x4 is meant to mean -5x^4, -20x or -20.  I'll assume -20:

9x-4y = -20

Put the equation into standard slope-intercept form:  Y = mx + b, where m is the slope and b is the y-intercept (the value of y when  x = 0).

-4y = -9x - 20

y = (9/4)x + 5

This line has a slope of (9/4).  The parallel line will have the same slope.

y = (9/4)x + b

We can find a value of b that would shift this line to include (4,7) by using this point in the equation:

y = (9/4)x + b

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5 0
3 years ago
Hi please i nedd help with these questions .
Vlad1618 [11]

Answer:

Step-by-step explanation:

#1:

\frac{18m^2u}{16n^3v^2} \div \frac{24m}{15nu^3}*\frac{8n^2v^3}{30m^3u}

division sign means that we flip the fraction

\frac{18m^2u}{16n^3v^2} * \frac{15nu^3}{24m}*\frac{8n^2v^3}{30m^3u}

now we can multiply all the constants together and all variables

m: (m^2)/(m*m^4) = (m^2)/(m^4) = 1/(m^2)\\u: (u * u^3)/(u) = (u^4)/(u) = u^3\\n: (n*n^2)/(n^3) = 1\\v: (v^3) / (v^2) = v\\(18*15*8)/(16*24*30) = \frac{3}{16}

now we can combine all the parts

\frac{3u^3v}{16m^2}

#2:

\frac{24a^2b^3c}{9bc^3}\div\frac{4a^5bc^3}{27a^3b^2c}

\frac{24a^2b^3c}{9bc^3}*\frac{27a^3b^2c}{4a^5bc^3}

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\frac{18b^3}{c^4}

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3 years ago
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