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mario62 [17]
3 years ago
13

If 2^a =0.5 and 5^b=125, what is the value of a^b +b^a?​

Mathematics
1 answer:
kifflom [539]3 years ago
3 0

9514 1404 393

Answer:

  -2/3

Step-by-step explanation:

  2^a = 0.5 = 2^-1   ⇒   a = -1

  5^b = 125 = 5^3   ⇒   b = 3

Then the expression a^b  +b^a is ...

  a^b +b^a = (-1)^3 +3^(-1) = -1 +1/3 = -2/3

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Highschool level trigonometry!!! Need help knowing step by step how to find answer!
Goshia [24]

Answer:

\theta \approx 82.34^\circ

Step-by-step explanation:

Please refer to the attached diagram. (Apologies if the shading or resolution is a bit off.)

So, we want to find θ.

Since we formed a right triangle, we can use right triangle ratios.

We know the measure of the adjacent side to θ and the hypotenuse.

Therefore, we will use the cosine ratio:

\displaystyle \cos(\theta)=\frac{\text{adjacent}}{\text{hypotenuse}}

The adjacent side is 2 and the hypotenuse is 15. By substitution:

\displaystyle \cos(\theta)=\frac{2}{15}

Now, we will take the inverse cosine of both sides. So:

\displaystyle \theta=\cos^{-1}\Big(\frac{2}{15}\Big)

Use a calculator. Hence:

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3 years ago
I do not need an explanation, just a simple angle number!
Murljashka [212]

Answer:

Step-by-step explanation:

a + 143 = 180    {Linear pair}

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c  + 40 = 90

c = 90 - 40

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d = 180 - 120

d = 60

? = 60 + 40         {Exterior angle property of triangle}

? = 100

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108 is the answer for this question
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Answer:

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3 years ago
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