Answer:
Therefore,

Step-by-step explanation:
Given:
![A=\left[\begin{array}{ccc}3&6&9\\2&4&8\\\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%266%269%5C%5C2%264%268%5C%5C%5Cend%7Barray%7D%5Cright%5D)
To Find:
a₂₁ = ?
Solution:
Let,
![A=\left[\begin{array}{ccc}a_{11}&a_{12}&a_{13}\\a_{21}&a_{22}&a_{23}\\\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da_%7B11%7D%26a_%7B12%7D%26a_%7B13%7D%5C%5Ca_%7B21%7D%26a_%7B22%7D%26a_%7B23%7D%5C%5C%5Cend%7Barray%7D%5Cright%5D)
We require ' a₂₁ ' i.e Second Row First Column Element
So on Comparing we get
∴ 
Therefore,

Answer:
The probability that at most 38 of the 60 relays are from supplier A is P(X≤38)=0.3409.
Step-by-step explanation:
We can model this question with a binomial distribution random variable.
The sample size is n=60.
The probability that the relay come from supplier A is p=2/3 for any relay.
If we use a normal aproximation, we have the mean and standard deviation:

The probability that at most 38 of the 60 relays are from supplier A is P(X≤38)=0.3409:

Answer:
8:4 simplified to 4:2 simplified to 2:1
Step-by-step explanation:
Answer:
Area of the shaded region= 
Step-by-step explanation:
Area of the shaded region=Area of the rectangle-Area of the circle
Area of rectangle= 

Area is:

Area of the circle = 

As, 
Area of the Circle is :

Area of the Shaded region:
Area of the shaded region