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Minchanka [31]
3 years ago
14

What is the approximate circumference of a circle that has a radius of 6 units? Round your answer to the nearest tenth.

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
8 0

Answer:

37.7 units²

Step-by-step explanation:

the formula for circumference of a circle is πr²

π x 6² = 37.69 ≈37.7²

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ad-work [718]
3) 4r⁻³ · 2r² = 4·2 r⁽⁻³⁺²⁾ = 8 r⁻¹ = 8/r

4) 8k⁵

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8 0
3 years ago
The graph shows the result of a matrix transformation, where the pre-image has dashed lines Which matrix operation is represente
diamong [38]

The <em>matrix operation</em> is the <em>addition subtraction </em>and <em>multiplication </em>involving matrices.  The coordinates of the <em>image </em>can be represented as a matrix obtained from the coordinates of the <em>preimage </em>through matrix operations

The best correct option is<u> option D)</u>,<em> (the y-coordinate for the point (8, -7) is to be replaced with a 7 to give (7, -7) as follows</em>:

\left[\begin{array}{rrrr}1&0\\0&-1\end{array}\right] \left[\begin{array}{rrrr}9&7&3&2\\-3&-7&-7&-5\end{array}\right]

The reason the above matrix value for the matrix operation are correct are as follows:

Known parameters:

From the diagram, we have that the <em>coordinates</em> of the vertices of the preimage are;

(2, -5), (3, -7), (9, -3), and (7, -7)

The <em>coordinates </em>of the vertices of the image are;

(2, 5), (3, 7), (9, 3), and (7, 7)

Required:

The matrix operation for the transformation of the preimage points to the image points

Solution:

The transformation from the coordinates of the vertices of primage to the  vertices of image involves the change in the sign from negative to positive, of the y-values of the image, which can be obtained by <em>multiplying by</em> (-1)

Therefore, the required matrix operation is presented as follows:

\mathbf{\left[\begin{array}{rrrr}1&0\\0&-1\end{array}\right] \left[\begin{array}{rrrr}9&7&3&2\\-3&-7&-7&-5\end{array}\right]} =\left[\begin{array}{rrrr}9&7&3&2\\3&7&7&5\end{array}\right]

Therefore, the <em>best correct</em> option is option D)

Learn more about matrix operations here:

brainly.com/question/17141646

3 0
3 years ago
Can anyone help me with my math equation?
Allisa [31]
What's the question?..
5 0
3 years ago
Stuck, anyone can help?
expeople1 [14]

Answer:

Step-by-step explanation:

\sqrt{x-3} = x - 5 ( x ≥ 3 )

( \sqrt{x-3} )² = ( x - 5 )²

x - 3 = x² - 10x + 25

x² - 11x + 28 = 0

(x - 4)(x - 7) = 0

x_{1} = 7

x_{2} = 4

Check the answer:

1). x = 7

\sqrt{7-3} = 7 - 2

√4 = 2

2 = 2

2). x = 4

\sqrt{4-3} = 4 - 5

1 = - 1 (False statement) ⇒ x = 4 is an extraneous solution.

6 0
3 years ago
For the following set of 20 numbers:
patriot [66]

Answer:

I cannot answer all of this, so I will only answer what I can:

Q1: 13

Q3: 22.5

IQR: 13.5

IQR(1.5): 20.25

Q3 + IQR(1.5) = 43

Q1 - IQR(1.5) = -7.25

I don't know if my calculations are all right but I hope this helps! :)

4 0
3 years ago
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