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abruzzese [7]
3 years ago
11

I need help with this

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
3 0

Answer:

nember 1: 2/7 as decimal

number 2: 2 1/6 as decimal

number 3: 3/16 as a decimal

number 4: 3/4 as a decimal

number 5: 5/10 as a decimal

number 6: 13 7/8 as a decimal

number 7: 8 10/15 as a decimal

number 8: 5/8 as a decimal

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The table shows the amount of money in your savings account over a period of 6
MatroZZZ [7]

Answer: N=800/5

N=160

He needs to save $160 every week to get $800 in 5 weeks

hope this helps.

7 0
3 years ago
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How to do this problem?
Anvisha [2.4K]
The measurement are the same. From 2,4,6,8. After you known those equal to 103. You know a line equals 180. So you would do 180-103=77. So from 1,3,5,7 will all be 77 degree.
5 0
3 years ago
9 = x/2 + 2<br> solve for x.
Leya [2.2K]

Answer:

14 = x

Step-by-step explanation:

-2 on both sides you get 7 = x/2, multiply both sides by 2 and you get 14 = x

8 0
4 years ago
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Suppose that you are in charge of evaluating teacher performance at a large elementary school. One tool you have for this evalua
Strike441 [17]

Answer:

a) Standard error = 2

b) Range = (76.08, 83.92)

c) P=0.69

d) Smaller

e) Greater

Step-by-step explanation:

a) When we have a sample taken out of the population, the standard error of the mean is calculated as:

\sigma_m=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10}{\sqrt{25}}=\dfrac{10}{5}=2

where n is te sample size (n=25) and σ is the population standard deviation (σ=10).

Then, the standard error of the classroom average score is 2.

b) The calculations for this range are the same that for the confidence interval, with the difference that we know the population mean.

The population standard deviation is know and is σ=10.

The population mean is M=80.

The sample size is N=25.

The standard error of the mean is σM=2.

The z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=1.96 \cdot 2=3.92

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 80-3.92=76.08\\\\UL=M+t \cdot s_M = 80+3.92=83.92

The range that we expect the average classroom test score to fall 95% of the time is (76.08, 83.92).

c) We can calculate this by calculating the z-score of X=79.

z=\dfrac{X-\mu}{\sigma}=\dfrac{79-80}{2}=\dfrac{-1}{2}=-0.5

Then, the probability of getting a average score of 79 or higher is:

P(X>79)=P(z>-0.5)=0.69146

The approximate probability that a classroom will have an average test score of 79 or higher is 0.69.

d) If the sample is smaller, the standard error is bigger (as the square root of the sample size is in the denominator), so the spread of the probability distribution is more. This results then in a smaller probability for any range.

e) If the population standard deviation is smaller, the standard error for the sample (the classroom) become smaller too. This means that the values are more concentrated around the mean (less spread). This results in a higher probability for every range that include the mean.

6 0
3 years ago
a zip line starts 35 feet above the ground and has one landing platform. The line is secured into the ground. what’s the height
ioda

Answer:

0 feet

Step-by-step explanation:

Because the landing platform is on the ground, it is 0 feet.

4 0
3 years ago
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