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Nana76 [90]
3 years ago
9

An object starts at x=-15.8m and ends at x=20.3m. what was its displacement(unit=m)

Mathematics
1 answer:
liubo4ka [24]3 years ago
6 0

36.1metres

15.8+20.3=36.1

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What is the word form of the number 602,107?
Nadusha1986 [10]
<span><u>Answer</u>
Six hundred and two thousand, one hundred and seven.

<u>Explanation </u>
When writing numbers in words you consider the place value of the digits forming that number. A digit is defined by its place value.
In the questions above, 6 is in hundred thousands place, 0 in ten thousands place, 2 in thousands place, 1 in hundreds place, 0 in tens place and 7 in ones place.
So, the 602, 107 in words is Six hundred and two thousand, one hundred and seven. 
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3 0
3 years ago
An amusement park charges $8 for admission and $2 for each ride. Use the graph to find the slope and the y-intercept. Then write
kupik [55]

Answer:

y=2x+8

Step-by-step explanation:

y=mx+b

M: cost for each ride, $2

B: Flat admission rate, $8

6 0
3 years ago
Last question please
MatroZZZ [7]

Let's try an make a formula to make things easy.

_________________________________________________

Look at Andrew's pattern, it goes up 6 every time. Lets look at the 6 times table

6 times table:           6, 12, 18, 24, ...

____________________________________

First think, how would you work out the <u>7</u>th term in the <u>6</u>th times table?

You would do <u>6</u> times <u>7</u>.

So the formula for the 6th times table is:

6n     (where n is the term you want to find out)

_______________________________________

So to get the 9th term in the 6 times table, you would replace the n with 9, like so:

9th term in 6 times table = 6 x 9 = 54

______________________________________

Now lets compare the 6 times table to Andrew's pattern:

6 times table:           6, 12, 18, 24,

Andrew's pattern:     3, 9, 15, 21,

_____________________________________

If you look, you can see that Andrew's pattern is the 6 times table minus 3!

So what would be the formula for Andrew pattern?

---> it would be:  6n - 3   (since it's the 6 times table but minus 3)

_____________________________________

We can use this formula to easily work out the 20th term in Andrew's pattern!:

20th term = 6 x 20 - 3 = 120 - 3 = <u>117</u>    (remember, replace the n with 20)

______________________________________

Now let's make a formula for Ben's pattern!

Ben's pattern goes up in 5s, so lets compare it to the 5 times table:

5 times table:       5, 10, 15, 20

Ben's pattern:       3, 8, 13, 18,

The formula for the 5 times table is 5n, and Ben's pattern is the 5 times table but minus 2.

So the formula for Ben's pattern is: 5n - 2

__________________________________

<u>Now swap out the n for 20</u>  (to get the 20th term):

20th term = 5 x 20 - 2 = 100 - 2 = <u>98</u>

_________________________________________

So Andrew's 20th term is <u>117</u>, and Ben's 20th term is <u>98</u>.

All we do now is subtract them to find the difference:

117 - 98 = <u>19</u>

- - - - - - - - - - - - - - - - - - - - - - - - -

Answer:

Ben's 20th term is smaller by 19!

- - - - - - - - - - - - - - - - - - - - - - - - - -

5 0
3 years ago
Adding and Subtracting Integers <br><br><br>(-5) + (+45)<br><br>(-5) + (+48)
timofeeve [1]
1. 40
2. 43
its just like subtracting when you add a negative number to a positive one. flip them around! makes it a lot easier.
7 0
3 years ago
In calendar year 2004, Division A of MegaStore increased its sales from $1.5 billion to $1.8 billion, and Division B increased i
german
A’s increase is 1.8/1.5=6/5; B’s increase is 1/0.6=5/3.
A formula for A is A(t)=1.5(6/5)^t and for B, B(t)=0.6(5/3)^t where t is years since 2004.
When A=B, 1.5(6/5)^t=0.6(5/3)^t.
Taking logs: log1.5+tlog(6/5)=log0.6+tlog(5/3), t(log(5/3)-log(6/5))=log1.5-log0.6.
tlog(25/18)=log2.5, t=log2.5/log(25/18)=2.7893 approx.
This occurs during 2006 around mid-October.
Common sales=1.5(6/5)^2.7893=0.6(5/3)^2.7893=$2.4943 billion.
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