An object starts at x=-15.8m and ends at x=20.3m. what was its displacement(unit=m)

Please help me out with this please

dedylja [7]

Intersecting Chord Theorem:

X = 1/2(78 + 76)

X = 1/2(154)

x = 77

3 0

3 years ago

What expression must the center cell of the table below contain so that the sums of each row, each column, and each diagonal are

sergey [27]

Oh, I adore magic squares!

We need all rows to be equivalent, so try adding up the bottom (complete) row to get 7x-4x+3x=10x-4x=6x.

To solve the middle number, we have -2x+X+6x=6x, so X=2x.
To solve the top number, we have X+8x-3x=6x, so X=6x-8x+3x=x

Now check first column,
x-2x+7x=6x ok
Second column
8x+2x-4x=6x ok
Top-right to bottom-right diagonal: x+2x+3x=6x, ok
Bottom-left to top right diagonal: 7x+2x-3x=6x

So everything is ok!

5 0

3 years ago

While conducting experiments, a marine biologist selects water depths from a uniformly distributed collection that vary between

Oksi-84 [34.3K]

The answer is 10 and 15%

4 0

3 years ago

Read 2 more answers

write and equation for the line in point-slope form that passes through (2,-5) and is perpendicular to the line 2x-4y+8=0

Ivenika [448]

bearing in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of the equation above?

$\bf 2x-4y+8=0\implies -4y=-2x-8\implies y = \cfrac{-2x-8}{-4} \\\\\\ y = \cfrac{-2x}{4}-\cfrac{8}{-4}\implies y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{1}{2}}x+2\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{1}{2}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{2}{1}}\qquad \stackrel{negative~reciprocal}{\cfrac{2}{1}\implies 2}}$

so we're really looking for the equation of a line whose slope is 2 and runs through (2,-5),

$\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{-5})~\hspace{10em} \stackrel{slope}{m}\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-5)}=\stackrel{m}{2}(x-\stackrel{x_1}{2}) \\\\\\ y+5=2x-4\implies y=2x-9$

4 0

3 years ago

What is the standard form of 30+5+2/10

Dvinal [7]

Order of operation says to divide 2 by 10 first. $\frac{2}{10} = \frac{1}{5}$

Now add the 30 + 5 and get 35 $\frac{1}{5}$ as your final answer

3 0

3 years ago