Please help me its 15 pts and brainlist

What is the value of x?<br><br> Please include steps on how to get to the answer. <3

AlekseyPX

We have that
<span>Bisector theorem--------------- >(LM)/(LN)=(OM)/(ON)
therefore
</span>(18)/(10)=(x)/(4)------------------ > x=7.2

the answer is x=7.2

6 0

3 years ago

HELPPPPPPPPPPPPPPPPPPP PLEASEEEE

Softa [21]

So half of Nina's age is 10/2= 5. And since Greg is three years younger we subtract from 5 like so...
10/2=5
5-3
2
So Greg is 2 years old. I hope this helps love! :)

5 0

2 years ago

Read 2 more answers

Consider the following function:y=1/(x+5)+2

Galina-37 [17]

Answer:

Step-by-step explanation:

Starting with the parent function, x was replaced by (x + 5), indicating that the graph of the new function is that of the old function shifted 5 units to the LEFT. That +2 shifts this result UP by 2 units.

8 0

2 years ago

Read 2 more answers

The cost of watching videos on a website is represented by C(a) = 3.00a + 4.00, where a is the number of videos watched. The cos

aksik [14]

Answer:

The answer is A; H(a) = 3.00a +19.00; shift 15 units up

Step-by-step explanation:

If the downloading feature is enabled the cost function becomes H(a) = 3.00a + 19.00

The y-interpret of H(a) is 15 greater than the y-intercept if C(a)

The slopes of both functions are the same

3 0

2 years ago

NarStor, a computer disk drive manufacturer, claims that the median time until failure for their hard drives is more than 14,400

Ne4ueva [31]

Answer:

The test statistics is $t = -1.727$

Step-by-step explanation:

From the question we are told that

The data given is

330 620 1870 2410 4620 6396 7822 81028309 12882 14419 16092 18384 20916 23812 25814

The population mean is $\mu = 14400$

The sample size is n = 16

The null hypothesis is $\mu \le 14400$

The alternative hypothesis is $H_a : \mu > 14400$

The sample mean is mathematically evaluated as

$\= x = \frac{\sum x_i}{n}$

So

$\= x = \frac{330+ 620+ 1870 +2410+ 4620+ 6396+ 7822+ 8102+8309+ 12882+ 14419+ 16092+ 18384 +20916+ 23812+ 25814 }{16}$

=> $\= x = 10799.9$

The standard deviation is mathematically represented as

$\sigma =\sqrt{\frac{ \sum (x_i - \=x)^2}{n}}$

So

$\sigma =\sqrt{\frac{(330- 10799.9)^2 + (620- 10799.9)^2+ (1870- 10799.9)^2 +(2410- 10799.9)^2 + (4620- 10799.9)^2 +(6396- 10799.9)^2 +(7822- 10799.9)^2 }{16}} \ ..$

$..\sqrt{ \frac{(8102 - 10799.9)^2 +(8309 - 10799.9)^2 + (12882 - 10799.9)^2 + (14419 - 10799.9)^2 + (16092 - 10799.9)^2 + (18384 - 10799.9)^2 +(20916 - 10799.9)^2 }{16}} \ ...$