Answer:
A minimum of 10 dimes and 11 quarters is what Alexandra will have
Step-by-step explanation:
Let
d = number of dimes
q = number of quarters
Since she has 21 coins altogether,
d + q = 21------------------------equation 1
- If these coins are worth $3.75 then
0.10 x d + 0.25 x q = 3.75
- which is 0.10d +.25q =3.75
--------------------------equation 2
where $.10 is the value of one dime and $.25 is the value of one quarter
make d the subject of formula from equation 1 d = 21 -q----------equation 3
insert it in equation 2
0.10d +0.25q =3.75
0.10(21-q) + 0.25q = 3.75
0.1(21)-0.1q+0.25q=3.75
2.1 +0.15q = 3.75
0.15q = 3.75-2.1 = 1.65
q = 1.65/0.15 =165/15 =11
- since we have the value of q insert in equation 3
d = 21 - q
d = 21-11
d = 10
Alexandra has 10 dimes and 11 quarters.
from my calculation i can see that the a minimum of 10 dimes and 11 quarters is what Alexandra will have
Answer: $40
Step-by-step explanation:
To find the whole number you divide the part by the percentage
so here it was 32/0.8
hope it helps
Okay well it kept saying that I for some reason was not using appropriate words so my long response got deleted.
tldr; we can treat this like a box that we put something into (x) and we get something back from it (y).
We can then take this data we get and put it in a table. This is useful for finding patterns.
I will post a picture of what a table may look like.
Hope this Helps!
Answer: $18
Explanation: 6x3
(3/5 + -1/4)/(7/10)
get a common denominator of 20
3/5 * 4/4 =12/20
-1/4 * 5/5 = -5/20
7/10 *2/2 = 17/20
replace
(12/20 - 5/20)/(14/20)
add the top
(7/20)/(14/20)
copy dot flip
7/20 * 20/14
7/14
1/2
