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joja [24]
3 years ago
15

HELP!! (Brianlist) PLEASE NOWW

Mathematics
2 answers:
Whitepunk [10]3 years ago
7 0

Answer:

3/6.

Step-by-step Explanation:

Are you d u m b, It shows you the answer.

Gwar [14]3 years ago
4 0

Answer:

3/6

Step-by-step explanation:

Because if you divide 3/6 by 2 you get 1/2

You might be interested in
D
yarga [219]

Answer:

I think the answer is 67.5. Hope this helps! :)

3 0
2 years ago
Boxes that are 18 inches tall are being stacked next to boxes that are 24 inches tall.What is the shortest height at which the t
Juli2301 [7.4K]

The shortest height at which the two stacks will be same is 72 inches.

Step-by-step explanation:

Given,

Boxes that are 18 inches tall are being stacked next to boxes that are 24 inches tall.

It means that we will find least common factor of both the boxes;

18 = 2*3*3

24 = 2*2*2*3

LCM = 2*2*2*3*3 = 72

The least common multiple of 18 and 24 is 72, therefore,

The shortest height at which the two stacks will be same is 72 inches.

Keywords: LCM, multiplication

Learn more about LCM at:

  • brainly.com/question/1560475
  • brainly.com/question/1561649

#LearnwithBrainly

4 0
4 years ago
Which is the solution to<br> 6x + 7 = 3(2x - 3)?.
IRINA_888 [86]

Answer:

For this, there is No Solution

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Please help the following questions
34kurt

Answer:

<em>Question 7. Option B,</em>

<em>Question 8. Option C</em>

Step-by-step explanation:

<em>Question 7.</em>

Let us create a proportionality, and solve for the value of s, through cross multiplication;

3 / 12 = s / 15,\\3 * 15 = 12 * s,\\12 * s = 45,\\\\s = 3.75\\\\Conclusion - Option B

<em>Question 8.</em>

We can solve this problem in a similar manner, through setting a proportionality and solving for the length of the shadow of the tree, which we can pose as x;

5 / 6 = 25 / x,\\5 * x = 6 * 25,\\5x = 150,\\\\x = 30 ft\\\\Conclusion - Option C

7 0
3 years ago
Make sure the answer is 100% correct. Then circle the answer in a circle.
Vladimir [108]

Answer:
False
Any integers that the numbers 5, 10 , 15 but 20 can be used as a counter argument against the statement.

Step-by-step explanation:

The claim is that A⊆B which stands for that A is a SUBSET in B, or that B contains A.

The truth is that B⊆A since 5 has more possible outcomes than 20 in the number of integers.
So the list of all possible answers are r5, r10, and r15 where N⊆Z.

For example I choose r=3 and r15, 3(15)= 45. I can use the number 45 as a counter argument that the statement of A⊆B is false.

6 0
2 years ago
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