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velikii [3]
2 years ago
12

Please be quick i dont have that much time

Mathematics
1 answer:
Oduvanchick [21]2 years ago
3 0

Answer:

To find the sum of interior angles in a polygon, we can use the formula:

180(n-2) where n is the number of sides.

Since this is pentagon (5 sides), then 180(5-2)=180*3=540

The missing angle would then be

540-97-111-104-115=113

Since angles on a straight line add up to 180, then

x+113=180

x=67

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When Matthew eats a pizza he always eats a whole slice at a time with no bites left over. Which graph best represents this situa
RoseWind [281]

Answer:

b

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
6x-3y= -6 for y can someone please help me
kifflom [539]

Answer:

y = 2 + 2x

Step-by-step explanation:

6x-3y= -6

-3y = -6 -6x

3y = 6 + 6x

y = 2 + 2x

5 0
3 years ago
Which sequence of transformations creates a similar but not congruent triangle
Gwar [14]

A a dilation and reflection

dilation will make bigger or smaller therefore it cannot be congruent


5 0
4 years ago
Read 2 more answers
Do not use your calculator for Parts 1 through 4.
Hunter-Best [27]
You have to understand how piecewise functions first
I hope you do because I won't be explaining it here



1.
if it is continiuous at x=1 then the part of the function that approaches 1 from the left is the same value
so we have f(x)=3-x for x<1, so evaluate it for x=1,
we would get 3-1=2
so
if a=2 and b=3

f(x)=2x²+3x
for x=1, we get 2+3=5

it approaches 2 from the left but equals 5
2≠5
so it is not continuous because it doesn't approach the same value at x=1




2.
alright
so we established that it should approach 2 because we had the f(x)=3-x
so
f(1)=2=ax²+bx
2=a+b
the relationship is 2=a+b



3.
same as before, but use the other function, the one that is defined at x≥2
5x-10, 5(2)-10, 10-10, 0
it approaches 0
so
we must find one such that f(x)=0 for x=2 with the ax²+bx
0=a(2)²+b(2)
0=4a+2b
if we minus 2b both sides
-2b=4a
divide by 2
-b=2a
add b both sides
0=2a+b



4.
2=a+b
0=2a+b

2=a+b
minus b both sides
2-b=a
subsitute
0=2a+b
0=2(2-b)+b
0=4-2b+b
0=4-b
b=4

sub back
2-b=a
2-4=a
-2=a

a=-2
b=4


5.
graph f(x)=-2x²+4x from x=1 to x=2 and put a closed dot at (1,2) and an open dot at (2,0)
4 0
3 years ago
Can someone explain this to me?
jenyasd209 [6]

Answer:

Step-by-step explanation:

a). By applying tangent rule in the triangle,

   tanθ = \frac{\text{Opposite side}}{\text{Adjacent side}}=\frac{3}{4}

   θ = \text{tan}^{-1}(\frac{3}{4})

   θ = 36.87°

   Therefore, θ < 45°

b). By using cosine rule in this triangle,

   cosθ = \frac{\text{Adjacent side}}{\text{Hypotenuse}}=\frac{18}{18\sqrt{2}}

   cosθ = \frac{1}{\sqrt{2}}

    θ = 45°

c). By using tangent rule,

  tanθ = \frac{\text{Opposite side}}{\text{Adjacent side}}=\frac{8}{2}

  θ = \text{tan}^{-1}(4)

  θ = 75.96°

  θ > 45°

4 0
3 years ago
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