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velikii [3]
2 years ago
12

Please be quick i dont have that much time

Mathematics
1 answer:
Oduvanchick [21]2 years ago
3 0

Answer:

To find the sum of interior angles in a polygon, we can use the formula:

180(n-2) where n is the number of sides.

Since this is pentagon (5 sides), then 180(5-2)=180*3=540

The missing angle would then be

540-97-111-104-115=113

Since angles on a straight line add up to 180, then

x+113=180

x=67

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<h2>        A = 132 cm²</h2>

Step-by-step explanation:

Area of the figure is a sum of area of rectangle 4 cm × 7 cm and trapezoid with bases of 19 cm i 7 cm and altitude of 8 cm.

Therefore:

A=7\cdot4+\dfrac{7+19}2\cdot8=28+26\cdot4=132

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A graduate class consists of six students. What is the probability that at least 5 of them are born either in April or in Octobe
nlexa [21]

Answer:

0.0671% probability that at least 5 of them are born either in April or in October

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they were born in April or October, or they were not. The probabilty of a student being born in April or October is independent of other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Probability of a student being born in April or October

April has 30 days, October 31

The year has 365 days. So

p = \frac{61}{365} = 0.167

A graduate class consists of six students.

This means that n = 6

What is the probability that at least 5 of them are born either in April or in October?

P(X \geq 5) = P(X = 5) + P(X = 6)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{6,5}.(0.167)^{5}.(0.833)^{1} = 0.000649

P(X = 6) = C_{6,6}.(0.167)^{6}.(0.833)^{0} = 0.000022

P(X \geq 5) = P(X = 5) + P(X = 6) = 0.000649 + 0.000022 = 0.000671

0.0671% probability that at least 5 of them are born either in April or in October

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