Given:
The figure of a rhombus QRST.
To find:
A. The value of x.
B. The measure of angle RQP.
Solution:
A. We need to find the value of x.
We know that the diagonals of a rhombus are perpendicular bisectors. It means the angles on the intersection of diagonals are right angles.
[Right angle]
Divide both sides by 5.
Therefore, the value of x is 15.
B. We need to find the measure of angle RQP.
From the given figure, it is clear that
Putting , we get
Therefore, the measure of angle RQP is 33 degrees.
Answer:
Step-by-step explanation:
A= a+b/2 h (area = a +b over 2 times H) plug in your numbers
I dont have a picture, if i did i could solve it, but here is the formula
Answer:x > -3
Step-by-step explanation:
Answer:
the answer should be -5x - 30 + 30 y
We know, S = n/2 [ a + l ]
Here, a = 45
l = 108
Calculation of n:
a(n) = a + (n - 1)d
108 = 45 + (n - 1)1
108 - 45 = n - 1
63 + 1 = n
n = 64
Now, substitute in the expression:
S = 64/2 [ 45 + 108 ]
S = 32 [ 153 ]
S = 4896
In short, Your Answer would be 4896
Hope this helps!
