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3 years ago

Please explain how to find the answer for this

Mathematics

1 answer:

FromTheMoon [43]3 years ago

5 0

$P(A \textrm{ and } B) = P(A) P(B|A)$

$P(A \textrm{ and } B) = \dfrac{3}{10} \cdot \dfrac{2}{5} = \dfrac{3}{25}$

Second to last choice.

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Which function represents g(x), a reflection of f(x) = 6(one-third) Superscript x across the y-axis?

Rasek [7]

The function $g(x)=6(3)^{x}$ represents a reflection of $f(x)=6(\frac{1}{3})^{x}$ across the y-axis ⇒ 3rd answer

Step-by-step explanation:

Let us revise the reflection across the axes

If the function f(x) reflected across the x-axis, then its image is g(x) = - f(x)
If the function f(x) reflected across the y-axis, then its image is g(x) = f(-x)

∵ $f(x)=6(\frac{1}{3})^{x}$

∵ g(x) is the image of f(x) after reflection across the y-axis

- From the rule above reflection across the y-axis changes the sign of x

∴ $g(x)=6(\frac{1}{3})^{-x}$

∵ $(a)^{-n}=(\frac{1}{a})^{n}$

∵ $(\frac{1}{a})^{-n}=(a)^{n}$

∴ $(\frac{1}{3})^{-x}=(3)^{x}$

∴ $g(x)=6(3)^{x}$

The function $g(x)=6(3)^{x}$ represents a reflection of $f(x)=6(\frac{1}{3})^{x}$ across the y-axis

Learn more:

You can learn more about reflection in brainly.com/question/5017530

#LearnwithBrainly

7 0

3 years ago

Read 2 more answers

One drumming pattern originating in Ghana can be played at 2.5 beats per second. To find the number of beats played in s seconds

Vikentia [17]

12 beats are played in 30 seconds

You would have to divide

30 / 2.5 = 12 beats

:)

8 0

3 years ago

Which of the values shown are potential roots of f(x) = 3x3 – 13x2 – 3x + 45? Select all that apply.

galina1969 [7]

Answer:

All potential roots are 3,3 and $-\frac{5}{3}$ .

Step-by-step explanation:

Potential roots of the polynomial is all possible roots of f(x).

$f(x)=3x^3-13x^2-3x+45$

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

p=All the positive/negative factors of 45

q=All the positive/negative factors of 3

$p=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45$

$q=\pm 1,\pm 3$

All possible roots

$\frac{p}{q}=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45,\pm \frac{1}{3},\pm \frac{5}{3}$

Now we check each rational root and see which are possible roots for given function.

$f(1)= 3\times 1^3-13\times 1^2-3\times 1+45\Rightarrow 32\neq 0$

$f(-1)= 3\times (-1)^3-13\times (-1)^2-3\times (-1)+45\Rightarrow \neq 32$

$f(-3)= 3\times (-3)^3-13\times (-3)^2-3\times (-3)+45\Rightarrow \neq -144$

$f(3)= 3\times (3)^3-13\times (3)^2-3\times (3)+45\Rightarrow =0\\\\ \therefore x=3\text{ Potential roots of function}$

Similarly, we will check for all value of p/q and we get

$f(-5/3)=0$

Thus, All potential roots are 3,3 and $-\frac{5}{3}$ .

5 0

3 years ago

Read 2 more answers

Please someone help me solve this. in graphic method.

fiasKO [112]

Answer:

just graph it mate

Step-by-step explanation:

5 0

3 years ago

Simplify this expression please and thank you

Sergeeva-Olga [200]

The answer is 2x-y

step-by-step explanation
in order to simplify you have to come one like terms and in this case you have your 3x and you’re subtracting x which is also know as 1x.
3x - 1x = 2x (then you still have your y) so 2x-y

8 0

2 years ago