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stiv31 [10]
3 years ago
10

what is the area of a trapezoid with bases of 8.2 CM + 5.9 cm and a height of 10 cm will mark brainiest

Mathematics
1 answer:
baherus [9]3 years ago
5 0
<span>Trapezoid area = ((sum of the bases) ÷ 2) • height
</span><span>Trapezoid area = [(8.2 + 5.9) /2] * 10
</span><span>Trapezoid area = (14.1 / 2) * 10
</span><span>Trapezoid area =7.05 * 10
</span><span>Trapezoid area = 70.50
</span>
Source:
http://www.1728.org/quadtrap.htm

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There are 32 students in a class. 12 of those students are girls what percent of the class are boys?
gtnhenbr [62]
You have 12 girls out of 32, so that's 20 boys. Take your amount of boys divided by your total number. So, 20/32 = .625
You want a percentage, so .625 x 100 = 62.5% boys
3 0
3 years ago
Please help, the brainiest will go to the one with a good answer.
Mashutka [201]
Option c is your answer 3xy + 7x4
3 0
3 years ago
Use the formula d=rt Find t for r = 48.3 m/h and d = 545.79 m.
djyliett [7]
D = 545.79
r = 48.3

Plug in numbers to corresponding variables

545.79 = t(48.3)

Isolate the t, divide 48.3 from both sides

(545.79)/48.3 = 48.3t/48.3

t = 545.79/48.3
t = 11.3

t = A) 11.3 h

hope this helps
8 0
3 years ago
A counselor at a community college claims that the mean GPA for students who have transferred to State University is more than 3
Lena [83]

Answer:

t=\frac{3.25-3.1}{\frac{0.3}{\sqrt{36}}}=3  

If we compare the p value and the significance level for example \alpha=1-0.99=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis.

And the best conclusion would be:

a) Yes. The counselor's claim is valid

Because we reject the null hypothesis in favor to the alternative hypothesis.

Step-by-step explanation:

Data given and notation  

\bar X=3.25 represent the sample mean

s=0.3 represent the sample standard deviation

n=36 sample size  

\mu_o =3.1 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is more than 3.1, the system of hypothesis would be:  

Null hypothesis:\mu \leq 3.1  

Alternative hypothesis:\mu > 3.1  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{3.25-3.1}{\frac{0.3}{\sqrt{36}}}=3  

P-value  

The first step is calculate the degrees of freedom, on this case:  

df=n-1=36-1=35  

Since is a one right tailed test the p value would be:  

p_v =P(t_{(35)}>3)=0.00247  

Conclusion  

If we compare the p value and the significance level for example \alpha=1-0.99=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis.

And the best conclusion would be:

a) Yes. The counselor's claim is valid

Because we reject the null hypothesis in favor to the alternative hypothesis.

5 0
3 years ago
What is 3x-8-8x=42 answer nowwwwwwwwwwwwwwwwwwwwwwwwwww
eimsori [14]

The answer is x = -10

Explanation:

3x-8-8x=42

3x-8x = 42-8

-5x = 50 ---> do

x = -10

4 0
2 years ago
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