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DochEvi [55]
3 years ago
6

You decide to take out an insurance policy that will

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
3 0
An atom can have five 5d orbitals. In fact, a d sublevels of an electron shell have five orbitals regardless of whether there are enough electrons to... An atom can have five 5d orbitals. In fact, a d sublevels of an electron shell have five orbitals regardless of whether there are enough electrons to... An atom can have five 5d orbitals. In fact, a d sublevels of an electron shell have five orbitals regardless of whether there are enough electrons to... An atom can have five 5d orbitals. In fact, a d sublevels of an electron shell have five orbitals regardless of whether there are enough electrons to... An atom can have five 5d orbitals. In fact, a d sublevels of an electron shell have five orbitals regardless of whether there are enough electrons to... An atom can have five 5d orbitals. In fact, a d sublevels of an electron shell have five orbitals regardless of whether there are enough electrons to...
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ladessa [460]

Given:

The equation of a line is:

y=-\dfrac{5}{7}x+2

A line passes through the point (-5,-3) and perpendicular to the given line.

To find:

The equation of the line.

Solution:

Slope intercept form of a line is:

y=mx+b                 ...(i)

Where, m is the slope and b is the y-intercept.

We have,

y=-\dfrac{5}{7}x+2          ...(ii)

On comparing (i) and (ii), we get

m=-\dfrac{5}{7}

We know that the product of slopes of two perpendicular lines is always -1.

m_1\times m_2=-1

-\dfrac{5}{7}\times m_2=-1

m_2=\dfrac{7}{5}

Slope of the required line is \dfrac{7}{5} and it passes through the point (-5,-3). So, the equation of the line is:

y-y_1=m_2(x-x_1)

y-(-3)=\dfrac{7}{5}(x-(-5))

y+3=\dfrac{7}{5}(x+5)

Using distributive property, we get

y+3=\dfrac{7}{5}(x)+\dfrac{7}{5}(5)

y+3=\dfrac{7}{5}x+7

y=\dfrac{7}{5}x+7-3

y=\dfrac{7}{5}x+4

Therefore, the equation of the line is y=\dfrac{7}{5}x+4. Hence, option A is correct.

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