You decide to take out an insurance policy that will

1 answer:

3 0

An atom can have five 5d orbitals. In fact, a d sublevels of an electron shell have five orbitals regardless of whether there are enough electrons to... An atom can have five 5d orbitals. In fact, a d sublevels of an electron shell have five orbitals regardless of whether there are enough electrons to... An atom can have five 5d orbitals. In fact, a d sublevels of an electron shell have five orbitals regardless of whether there are enough electrons to... An atom can have five 5d orbitals. In fact, a d sublevels of an electron shell have five orbitals regardless of whether there are enough electrons to... An atom can have five 5d orbitals. In fact, a d sublevels of an electron shell have five orbitals regardless of whether there are enough electrons to... An atom can have five 5d orbitals. In fact, a d sublevels of an electron shell have five orbitals regardless of whether there are enough electrons to...

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Mr. Hendricks is plotting equivalent ratios on a coordinate plane. One of the ordered pairs is (3,5) Which other ordered pair co

madam [21]

Answer:

(6, 10)

Step-by-step explanation:

(6, 10) because it can go in a straight line in the same rate.

4 0

3 years ago

CosA + cosB + cosC = 1 + 4sinA/2 sinB/2 sinC/2

bulgar [2K]

$\cos(A) + \cos( B ) + \cos(C) \\ = 2 \cos( \frac{A + B}{2} ) \cos( \frac{ A- B}{2} ) + 1 - 2 { \sin }^{2} \frac{C}{2} \\ = 1 + 2\cos( \frac{\pi - C}{2} ) \cos( \frac{A - B}{2} ) - 2 { \sin }^{2} \frac{C}{2} \\ = 1 + 2 \sin \frac{C}{2} \cos( \frac{A - B}{2} ) - 2 { \sin }^{2} \frac{C}{2} \\ = 1 + 2 \sin \frac{C}{2} [ \cos( \frac{A - B}{2} ) - \sin \frac{C}{2}] \\ = 1 + 2 \sin \frac{C}{2} [ \cos( \frac{A - B}{2} ) - \cos( \frac{A + B}{2} )] \\ = 1 + 2 \sin\frac{C}{2} \times 2 \sin( \frac{ \frac{A + B}{2} +\frac{A - B}{2} }{2} ) \sin( \frac{ \frac{A + B}{2} - \frac{A - B}{2} }{2} ) \\ = 1 + 4 \sin \frac{A}{2} \sin \frac{B}{2} \sin \frac{C}{2}$