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Tamiku [17]
3 years ago
11

There are 16 boys and 18 girls in a grade 6 math class . write the ratio of girls to boys in words as simply as possible

Mathematics
1 answer:
dimulka [17.4K]3 years ago
3 0

Answer:

8:9 = eight to nine

Step-by-step explanation:

16:18 - divide each by 2 in order to simplify

= 8:9

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Which are diagonals through the interior of the cube?<br> Select all the apply
Gennadij [26K]

Answer:

AH

Step-by-step explanation:

From the figure we can see a cube ABCDEFGH.

In a cube thee are 4 interior diagonals

To find the diagonal of the cube

AH, BG, CF   and DE

There are 4 interior diagonals.

The given options contain only one interior diagonal.

Therefore the correct answer is first option. AH

5 0
4 years ago
The ratio of 8 melons to 36 fruits​
Ivenika [448]

8/36

= 2/9 after dividing by 4

Please mark as brainliest.

4 0
3 years ago
Read 2 more answers
I just need to find this data set out, please anyone?​
rewona [7]

Answer:

Ok so...

Mean: 68.76

Median: 72

Range: 85

Step-by-step explanation:

3 0
3 years ago
Check my answer? Please, no joking around guys.
WITCHER [35]
This is a right angle triangle 
So we can use the tangent 
tan x = 5/20 
tan x= 0.25 
x=tan^-1 (0.25) 
x= 14.04 degrees 
So yes you're correct
3 0
3 years ago
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The following are the ages of 13 history teachers in a school district. 24, 27, 29, 29, 35, 39, 43, 45, 46, 49, 51, 51, 56 Notic
pishuonlain [190]

The five-number summary and the interquartile range for the data set are given as follows:

  • Minimum: 24.
  • Lower quartile: 29.
  • Median: 43.
  • Upper quartile: 50.
  • Maximum: 56.
  • Interquartile range: 50 - 29 = 21.

<h3>What are the median and the quartiles of a data-set?</h3>

  • The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.
  • The first quartile is the median of the first half of the data-set.
  • The third quartile is the median of the second half of the data-set.
  • The interquartile range is the difference between the third quartile and the first quartile.

In this problem, we have that:

  • The minimum value is the smallest value, of 24.
  • The maximum value is the smallest value, of 56.
  • Since the data-set has odd cardinality, the median is the middle element, that is, the 7th element, as (13 + 1)/2 = 7, hence the median is of 43.
  • The first quartile is the median of the six elements of the first half, that is, the mean of the third and fourth elements, mean of 29 and 29, hence 29.
  • The third quartile is the median of the six elements of the second half, that is, the mean of the third and fourth elements of the second half, mean of 49 and 51, hence 50.
  • The interquartile range is of 50 - 29 = 21.

More can be learned about five number summaries at brainly.com/question/17110151

#SPJ1

3 0
2 years ago
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