Applying parallel line postulate twice
36degree=3x degree +2y degree
126 degrees=12 x degree + 2y degree
So, the two equations are:
3x + 2y = 36
and
12x + 2y = 126
Eliminate x to solve for y
-(3x + 2y)= -(36)
-3x - 2y = -36
Combine the equations
(-3x - 2y)+ (12x + 2y) = (-36) + (126)
-3x -2y + 12x + 2y = -36 + 126
9x = 90
x = 10
Plug value of x back into to the equations to solve for y
3(10) + 2y = 36
30 + 2y = 36
2y =6
y = 3
Optional
Plug x into the other equation to check for error
12(10) +2y = 126
120 + 2y =126
2y = 6
y = 3
If you need the steps on how to get to 48 from 12, just multiply 12x4. Idk if that's what you need lol
Least common multiple is both will multiply in to 30 but 10 will not multiply into 12.so the answer is 30
For this, all you have to do is create equations where all you have to do is change the x value. The equation for gym A would be 35 + 42x, where x is the number of months he has the membership, and the first number is the initial fee. The equation for gym B would be 65 + 36x, following the same rules. Now all you have to do is set both of these equations equal to each other:
65+36x=35+42x
Solving this equation results in x=5, which means that he has to have the memberships for 5 months for them to be equal. Now just plug that in to one side of the equation to get the amount he has to spend:
65+36(5) = $245
