What is the remainder when 73,847 is divided by 43? Enter your answer as a whole number in the box
1 answer:
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Answer:
Step-by-step explanation:
Total possibilities when we a roll a die at a time are 6
given we should have four for first time and then three
let us assume we rolled the dice we may get 1,2,3,4,5,6(any of these) the probability to get 4 is
PROBABILITY=
Favourable chances=1
Total chances=6
Probability=
the prabability to get 4 in first roll is .
let us assume we rolled the dice for second time again we may get 1,2,3,4,5,6(any of these) the probability to get 3 is
Favourable chances=1
total chances=6
probability=
the probability to get 3 in second roll irrespective of first one is
the probability to get 4 in first time and then 3 is
The probability to occur both events at a time is multiplication of individual probabilities
So,
probablility to get 4 in first roll=
probability to get 3 in second roll=
probability to occur both at a same time is =
=
Answer:
= 4n - 13
Step-by-step explanation:
There is a common difference d between consecutive terms , that is
d = - 5 - (- 9) = - 1 - (- 5) = 3 - 1 = 7 - 3 = 4
This indicates the sequence is arithmetic with n th term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = - 9 and d = 4, thus
= - 9 + 4(n - 1) = - 9 + 4n - 4 = 4n - 13