The temperature outside is currently 10°F. It will fall at a constant rate of 3°F per hour. Which temperature will it be in 4 ho
1 answer:
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Answer:
2x - y - 3z = 0
Step-by-step explanation:
Since the set
{i, j} = {(1,0), (0,1)}
is a base in
and F is linear, then
<em>{F(1,0), F(0,1)} </em>
would be a base of the plane generated by F.
F(1,0) = a+b = (2i-2j+k)+(i+2j+k) = 3i+2k
F(0,1) = a+c = (2i-2j+k)+(2i+j+2k) = 4i-j+3k
Now, we just have to find the equation of the plane that contains the vectors 3i+2k and 4i-j+3k
We need a normal vector which is the cross product of 3i+2k and 4i-j+3k
(3i+2k)X(4i-j+3k) = 2i-j-3k
The equation of the plane whose normal vector is 2i-j-3k and contains the point (3,0,2) (the end of the vector F(1,0)) is given by
2(x-3) -1(y-0) -3(z-2) = 0
or what is the same
2x - y - 3z = 0
Answer:
B
Step-by-step explanation:
Consider all options:
A. Transformation with the rule
is a reflection across the x-axis.
Reflection across the x-axis preserves the congruence.
B. Transformation with the rule
is a dilation with a scale factor of over the origin.
Dilation does not preserve the congruence as you get smaller figure.
C. Transformation with the rule
is a translation 6 units to the right and 4 units down.
Translation 6 units to the right and 4 units down preserves the congruence.
D. Transformation with the rule
is a clockwise rotation by angle over the origin.
Clockwise rotation by angle over the origin preserves the congruence.