Answer:1: 36milimeters 2. 3,6 centimeters 3. 5milimeters 4. .5centimeters 5. 50milimeters 6. 5centimeters
Step-by-step explanation:
Answer:
Part A
6/40 = 0.15
Part B
16/40 = 0.4
Part C
10/40 = 0.25
Part D
8/40 = 0.20
Part E
The relative frequency of drawing a five-dollar bill is higher than the other relative frequencies. So, I can predict that Pablo is most likely to have more five-dollar bills than any of the others.
Part F
The relative frequency of drawing a one-dollar bill is lower than the other relative frequencies. So, I can predict that Pablo is most likely to have fewer one-dollar bills than bills of any other denomination.
Part G
It would not be a surprise if Pablo had fewer twenties than ones. The experiment was conducted only 40 times, and the numbers of times one-, ten-, and twenty-dollar bills were drawn are not very far apart. So, the number of twenties could be more or less than the number of ones. The same goes for tens and ones.
If you're on Plato an on slide 20 this Answer is for you:
<em>If Pablo does an experiment 100 times, will the relative frequency be more accurate or less accurate than if he did the experiment 40 times? Why?</em>
Answer: As the number of trials increases, the relative frequency becomes closer to the probability of the event. So, the relative frequency would be more accurate if the experiment were repeated 100 times rather than 40 times.
Answer:
1
Step-by-step explanation:
The tenths place is on the other side of the decimal so you have to star from 3. if the 3 was the number 5 or higher you would round the 9 up to ten, but since it is lower you leave the 9 alone and then move on to the next number which is 5. The 5 would be rounded up to 6 because the 9 next to it is higher than 5. So far you have 0.6. looking at the 0 we would round up to 1 because the 6 is higher than 5. the result is 1.0 or 1.
Okay here:
Let L be the length and W the width of the rectangle.
1. w=2•L
2. 2L+2W=36
Substitute eq. 1 into eq. 2,
2L+2•(2•L)=36
2L+4L=36
6L=36
L=9
Not done yet, then from eq. 1,
W=2•L
W=2•9
W=18 <------- Your answer. :)
Correct option C) 0.98%
<u>Step-by-step explanation:</u>
We know that , there are 2 black ace cards out of 52 cards in a deck & 13 hearts out of 52 cards . Here we have to tell What is the probability of drawing a black ace followed by a heart out of a deck when the cards aren't replaced . Let's find out:
Firstly , a black ace is drawn , so probability :
⇒ 
Now , A heart is drawn out of 51 cards ( as one black ace is already drawn !):
⇒ 
So , Probability of occurring both events is :
⇒ 
⇒ 
⇒ 
Percentage = 
%
Therefore , Correct option C) 0.98%
