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3 years ago

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10 cards are numbered from 1 to 10 and placed in a box. One card is selected at random and is not replaced. Another card is then

randomly selected. What is the probability of selecting two prime numbers?

1 answer:

blondinia [14]3 years ago

8 0

Answer is 8, and 2 hope this helps

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PLZ ANSWER APSP IM IN THE TEST RN!!!

olchik [2.2K]

Answer:

x = 38

y = 25

Step-by-step explanation:

To find x, you do

(2x + 5) = (3x - 33)

Subtract 2x from both sides to isolate x on one side, you get:

5 = (x - 33)

Add 33 to both sides to separate the normal number from the x, you get:

38 = x

From there, you plug x into one of the equations

2(38) + 5

The answer's 81, meaning that angle is 81 degrees. Using supplementary angles, you can find that angle ACD = 99, which you can use to find angle BCE. You'll get this equation:

(4y - 1) = 99

Add one to both sides to get rid of it, you get:

4y = 100

Divide by four, to get the y all alone:

y = 25

I hope this helped!

8 0

4 years ago

Read 2 more answers

Add and simplify

Tanya [424]

Answer:

Your 1st answer is correct

Step-by-step explanation:

$\frac{1}{(x - 1)} - \frac{3}{(1 - x)} + 2$

$\frac{1}{(x - 1)} - \frac{3}{ - (x - 1)} + 2$

$\frac{1}{(x - 1)} + \frac{3}{(x - 1)} + 2$

$\frac{4}{(x - 1)} + 2$

$\frac{4 + 2(x - 1)}{x - 1}$

$\frac{4 + 2x - 2}{x - 1}$

$= \frac{2x + 2}{x - 1}$

$= \frac{2(x + 1)}{x - 1}$

6 0

2 years ago

What does it mean for two fractions to be equivalent? For two ratios to be equivalent?

nadya68 [22]

When two fractions are equivalent that means that different fractions have the same number

6 0

4 years ago

Evaluate the function

Alja [10]

I don't know a lot about math

8 0

3 years ago

can anyone help me with this ??

Mars2501 [29]

Answer:

A. 336

B. Arranging 3 people in 8 chairs.

C. 42

B. Arranging 2 people in 7 chairs.

Step-by-step explanation:

A.

$P(n, r) = P(8, 3)$

Formula for Permutation is given as:

$P(n, r) = \dfrac{n!}{(n-r)!}$

Putting the value of $n$ = 8 and $r =3$ , we get:

$P(8, 3) = \dfrac{8!}{(8-3)!} \\\Rightarrow \dfrac{8\times 7 \times 6 \times 5\times 4 \times 3 \times 2\times 1}{5\times 4 \times 3\times 2\times 1}\\\Rightarrow 8\times 7 \times 6 \\\Rightarrow 336$

B. Real world situation for part A:

Arranging 3 people on 8 chairs.

First person has 8 options.

Second person has 7 options.

Third person has 6 options.

C.

$P(n, r) = P(7, 2)$

Formula for Permutation is given as:

$P(n, r) = \dfrac{n!}{(n-r)!}$

Putting the value of $n$ = 7 and $r$ = 2 , we get:

$P(7, 2) = \dfrac{7!}{(7-2)!} \\\Rightarrow \dfrac{7 \times 6 \times 5\times 4 \times 3 \times 2\times 1}{5\times 4 \times 3\times 2\times 1}\\\Rightarrow 7 \times 6 \\\Rightarrow 42$

D. Real world situation for part AC:

Arranging 2 people on 7 chairs.

First person has 7 options.

Second person has 6 options.

4 0

3 years ago