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11Alexandr11 [23.1K]
3 years ago
5

7. Sarah draws a card from a standard deck, throws the card away, and then draws another card.

Mathematics
1 answer:
VashaNatasha [74]3 years ago
7 0

Answer:

dependent

Step-by-step explanation:

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An electronics hobbyist has three electronic parts cabinets with two drawers each.
Andrews [41]

Answer:

a) 0.5 = 50% probability that an NPN transistor will be selected.

b) 0.3333 = 33.33% probability that it came from the cabinet that contains both types

c) 66.67% probability that it comes from the cabinet that contains only NPN transistors

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

a) What is the probability that an NPN transistor will be selected?

1/3 probability that the first cabinet is chosen. This cabinet has two transistors, both of which are NPN, so 100% probability of selecting a NPN transistor.

1/3 probability that the second cabinet is chosen. This cabinet has two transistors, both of which are PNP, so 0% probability of selecting a NPN transistor.

1/3 probability that the second cabinet is chosen. This cabinet has two transistors, one of which is NPN, so 50% probability of selecting a NPN transistor.

So

p = \frac{1}{3}*1 + \frac{1}{3}*0 + \frac{1}{3}*0.5 = \frac{1}{3} + \frac{1}{6} = \frac{2}{6} + \frac{1}{6} = \frac{3}{6} = 0.5

0.5 = 50% probability that an NPN transistor will be selected.

b) Given that the hobbyist selects an NPN transistor, what is the probability that it came from the cabinet that contains both types?

Here we use the conditional probability formula.

Event A: NPN transistor

Event B: From the third cabinet.

50% probability that an NPN transistor will be selected, so P(A) = 0.5.

1/6 probability that it is from the third cabinet and NPN, so P(A \cap B) = \frac{1}{6}

The desired probability is:

P(B|A) = \frac{\frac{1}{6}}{0.5} = 0.3333

0.3333 = 33.33% probability that it came from the cabinet that contains both types.

c) Given that an NPN transistor is selected what is the probability that it comes from the cabinet that contains only NPN transistors?

Either it comes from the cabinet with only NPN transistors, or it comes from the cabinet with both types of transistors. The sum of the probabilities of these outcomes is 100%. So

x + 33.33 = 100

x = 66.67

66.67% probability that it comes from the cabinet that contains only NPN transistors

6 0
3 years ago
If the measure of a tangent-chord angle is 74, then what is the measure of the intercepted arc inside the angle
Vedmedyk [2.9K]
The measure of the intercepted arc is twice the measure of the tangent-chord angle:
  2×74° = 148°

The measure of the intercepted arc is 148°.
7 0
3 years ago
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HELP PLEASE! I would really appreciate it :)
dem82 [27]
Each time x increases by 2 (eg: from x = -3 to x = -1), the value of y increases by 7 (eg: y = 9.5 to y = 16.5)

Change in y = 7
change in x = 2
Slope = (change in y)/(change in x) = 7/2 = 3.5

This all means that we have a linear equation
4 0
3 years ago
Which one is the answer?
ziro4ka [17]
Answer: its B because it does not pass the vertical line test
6 0
2 years ago
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How long have the nashville predators been a team?
olganol [36]
This is the Internet. It's really easy to look up.

3 0
4 years ago
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