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alexandr1967 [171]
3 years ago
11

Janine is packing carrots. Each large box holds 20 2-pound bags of carrots. If Janine has 800 bags of carrots, how many boxes ca

n she fill?
Mathematics
1 answer:
Darina [25.2K]3 years ago
5 0

Answer: 40 Boxes

Step-by-step explanation: All you need to do is divide 800 by 20.



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How do I answer this question?
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Answer:

The total cost for 8 skiers=316 dollars

Step-by-step explanation:

Given that the expression 15n+12n+100 represents the total cost in dollars for skis,boots and a lesson for n skiers.

To simplify the given expression :

15n+12n+100=27n+100

27n=-100

Therefore n=\frac{-100}{27}

Now to find the total cost for 8 skiers.

The total cost for 8 skiers can be written as below

Put n=8 in the given expression 15n+12n+100

15(8)+12(8)+100

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Therefore the total cost for 8 skiers is 316 dollars

The total cost for 8 skiers=316 dollars

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At an amusement park, 8 out of 80 tickets sold were discount tickets. What percentage of the tickets were discount tickets?
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Which statement is true about the value of (6-n)(6n)
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7 0
3 years ago
A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 420 gram setting. It is
anastassius [24]

Answer:

t=\frac{424-420}{\frac{26}{\sqrt{61}}}=1.202    

p_v =2*P(t_{(60)}>1.202)=0.234  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the true mean is NOT different from  420. So the specification is satisfied.

Step-by-step explanation:

Data given and notation  

\bar X=424 represent the sample mean

s=26 represent the sample standard deviation

n=61 sample size  

\mu_o =420 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is different from 420 or not, the system of hypothesis would be:  

Null hypothesis:\mu = 420  

Alternative hypothesis:\mu \neq 420  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{424-420}{\frac{26}{\sqrt{61}}}=1.202    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=61-1=60  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(60)}>1.202)=0.234  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the true mean is NOT different from  420. So the specification is satisfied.

4 0
3 years ago
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