Answer:
a) 0.0954
b) 0.9045
c) 0.1601
Step-by-step explanation:
We are given the following information:
We treat first-year students having computers as a success.
P(first-year students have computers) = 54.3% = 0.543
Then the number of first year students follows a binomial distribution, where
where n is the total number of observations, x is the number of success, p is the probability of success.
Now, we are given n = 3
a) P(None have computers)
b) P(At least one has a computer)
c) P(All have computers)
" 0.83 " MEANS " 83/100 ". They are identical quantities, because they are the SAME quantity.
Simplified Expression: 80x-2