27 degrees add four then 23 and you get 27
Answer:
g(-1) = -1
g(-0.25) = 0
g(2) = 2
Step-by-step explanation:
Answer:
596.34m approx
Step-by-step explanation:
Given data
Let the Starting point be x
A helicopter flew north 325 meters from x
Then flew east 500 meters
Let us apply the Pythagoras theorem to solve for the resultant which is the distance from the starting position
x^2= 325^2+500^2
x^2=105625+250000
x^2= 355625
x= √355625
x=596.34m
Hence the distance from the starting point is 596.34m approx
The answer is the square root of 101.75
Assuming that the sandwich Is a square, after cutting it diagonally, it turns into 2 triangles. To look for a missing length of a triangle, you use Pythagorean’s theorem a^2+b^2=c^2
Since c is 12 and a is 6.5 you just square 12 and square 6.5
144 42.25
Subtract it
101.75
You then have to find the square root of it. You can leave it as it is as √101.75 or just solve for it and round it to 10.09
So here we use the pythagorean theorem which is a2 + b2 = c2 (“a” squared times “b” squared equals “c” squared) the length from calvins house to the intersection is “a” and the length from phoebes house to the intersection is “b” so in order to find out the length of “c” (calvins house to phoebes house) we need to use the pythagorean theorem
a2 275x275=75,625
b2 113x113 = 12,769
so now that we have figured out what a2 and b2 are let’s add them
75,625 + 12,769 = 88,394
now since we only need to find out the length and not the area we need to find the square root of 88,394
the square root of 88,394 is 297.311 (i cut off the decimal after three places)
the direct length from phoebes house to calvins is 297.311 meters
