Answer:
yea ur correct
Step-by-step explanation:
use PhotoMath or something like that to check next time, it'll save a lot of time
Answer:
E[T] = 10
Step-by-step explanation:
A distribution is called uniform if each outcome has the same probability of happening.
The uniform distribution has two bounds, a and b, and the expected value of the uniform distribution is given by:

Uniformly distributed between 0 and 20 minutes.
This means that 
Let T be the number of minutes you wait until you board a bus. Find E[T].
This is
![E[T] = \frac{a + b}{2} = \frac{0 + 20}{2} = 10](https://tex.z-dn.net/?f=E%5BT%5D%20%3D%20%5Cfrac%7Ba%20%2B%20b%7D%7B2%7D%20%3D%20%5Cfrac%7B0%20%2B%2020%7D%7B2%7D%20%3D%2010)
E[T] = 10
Kiddo, you didn't draw the model that why
Answer:
Positive steady ncreasing slope!!
Answer:
<h2><em>
2ft by 2ft by 1 ft</em></h2>
Step-by-step explanation:
Total surface of the cardboard box is expressed as S = 2LW + 2WH + 2LH where L is the length of the box, W is the width and H is the height of the box. Since the cardboard box is without a lid, then the total surface area will be expressed as;
S = lw+2wh+2lh ... 1
Given the volume V = lwh = 4ft³ ... 2
From equation 2;
h = 4/lw
Substituting into r[equation 1;
S = lw + 2w(4/lw)+ 2l(4/lw)
S = lw+8/l+8/w
Differentiating the resulting equation with respect to w and l will give;
dS/dw = l + (-8w⁻²)
dS/dw = l - 8/w²
Similarly,
dS/dl = w + (-8l⁻²)
dS/dw = w - 8/l²
At turning point, ds/dw = 0 and ds/dl = 0
l - 8/w² = 0 and w - 8/l² = 0
l = 8/w² and w =8/l²
l = 8/(8/l² )²
l = 8/(64/I⁴)
l = 8*l⁴/64
l = l⁴/8
8l = l⁴
l³ = 8
l = ∛8
l = 2
Hence the length of the box is 2 feet
Substituting l = 2 into the function l = 8/w² to get the eidth w
2 = 8/w²
1 = 4/w²
w² = 4
w = 2 ft
width of the cardboard is 2 ft
Since Volume = lwh
4 = 2(2)h
4 = 4h
h = 1 ft
Height of the cardboard is 1 ft
<em>The dimensions of the box that requires the least amount of cardboard is 2ft by 2ft by 1 ft</em>