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3 years ago

Someone gets a test with 36 problems she got 20 of the problems correct what’s her grade

Mathematics

2 answers:

Mashutka [201]3 years ago

4 0

Answer:

If someone got 20 out of 36 problems correct, her grade would be about 55%.

Step-by-step explanation:

20 divided by 36 is 0.55555 and would keep going on, but since this is a percentage just move the decimal point to the right. It gives you 55%, and rounded up to the nearest tenths the score would be 56%.

Vlad [161]3 years ago

3 0

Answer:

If someone gets a 20 out of 36 on their test, their score is a 55%

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Ostrovityanka [42]

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3 years ago

Read 2 more answers

The diameter of a quarter is 24.26 mm and the diameter of a nickel is 21.21 mm. How much bigger is the distance around a quarter

olga55 [171]

Answer:

9.577 mm.

Step-by-step explanation:

We have been given that the diameter of a quarter is 24.26 mm and the diameter of a nickel is 21.21 mm.

Let us find the circumference of quarter and nickel using circumference of circle formula.

$\text{Circumference of circle}=2\pi r$ , where r represents radius of the circle.

Since we know that diameter of circle is 2 times its radius, so let us find radius of quarter and nickel by dividing their diameter by 2.

$\text{Radius of quarter}=\frac{24.26}{2}$

$\text{Radius of quarter}=12.13$

$\text{Radius of nickel}=\frac{21.21}{2}$

$\text{Radius of nickel}=10.605$

$\text{Circumference of quarter}=2\times 3.14\times 12.13$

$\text{Circumference of quarter}=76.1764$

Therefore, circumference of quarter is 76.1764 mm.

Let us find circumference of nickel.

$\text{Circumference of nickel}=2\times 3.14\times 10.605$

$\text{Circumference of nickel}=66.5994$

Let us subtract circumference of nickel from circumference of quarter.

$\text{The difference between distance around quarter and nickel}=76.1764-66.5994$

$\text{The difference between distance around quarter and nickel}=9.577$

Therefore, the distance around a quarter is 9.577 millimeters bigger than a nickel.

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4 years ago

What is the answer to (-2)^3-2^3

ANEK [815]

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3 years ago

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Aneli [31]

Answer:

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Step-by-step explanation:

9x^2y^2/x^2y^2=9

5x^2y^2/x^2y^2=5

since 9 and 5 have no common factors except 1, x^2 y^2

mark as brainliest plz

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