In this case, we will use our Pythagorean Theorem.
a = 84
b = 13
c = x

Thus,
x = 85.
Answer:
9.577 mm.
Step-by-step explanation:
We have been given that the diameter of a quarter is 24.26 mm and the diameter of a nickel is 21.21 mm.
Let us find the circumference of quarter and nickel using circumference of circle formula.
, where r represents radius of the circle.
Since we know that diameter of circle is 2 times its radius, so let us find radius of quarter and nickel by dividing their diameter by 2.






Therefore, circumference of quarter is 76.1764 mm.
Let us find circumference of nickel.

Let us subtract circumference of nickel from circumference of quarter.


Therefore, the distance around a quarter is 9.577 millimeters bigger than a nickel.
Approaching algebraicly(Take 2 as x)
(-x)^3-x^3
Simplify
Result is -2x^3
Put back 2
-2(2)^3 = -2(8)
= -16
Answer:
x^2 y^2
Step-by-step explanation:
9x^2y^2/x^2y^2=9
5x^2y^2/x^2y^2=5
since 9 and 5 have no common factors except 1, x^2 y^2
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2, 3, 5. I just solved them and they look equivalent.