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monitta
3 years ago
15

Pleaseeee help What one are equivalent?

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
7 0
2, 3, 5. I just solved them and they look equivalent.
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Fit a quadratic function to these three points:<br> (-2,8), (0, -4), and (4, 68)<br> Respuesta
zloy xaker [14]

Answer:

f(x) = 4x^2 + 2x - 4.

Step-by-step explanation:

Let the quadratic function be y = f(x) = ax^2 + bx + c.

For the point (-2, 8)  ( x = -2 when y = 8) we have:

a(-2)^2 + (-2)b + c = 8

4a - 2b + c = 8      For (0, -4) we have:

0 + 0 + c = -4   so c = -4.    For (4, 68) we have:

16a + 4b + c = 68  

So we have 2 systems of equations in a and b ( plugging in c = -4):

4a - 2b - 4 = 8

16a + 4b - 4 = 68

4a - 2b = 12

16a + 4b = 72    Multiplying 4a - 2b = 12 by 2 we get:

8a - 4b = 24  

Adding the last 2 equations:

24a = 96

a = 4

Now plugging a = 4 and c = -4 in the first equation:

4(4) - 2b - 4 = 8

-2b = 8 - 16 + 4 = -4

b = 2.

3 0
3 years ago
Javier monthly net income is $1,500. He requests that his bank deposit 1/5 of his monthly earnings into his savings account. how
Harman [31]
1500 * 1/5
1500 * 0.2 = 300
300 * 12 = 3600
Javier contributes $3,600 a year to his savings.
5 0
2 years ago
What is the solution to equation 8-2x+6=24
ki77a [65]

8 - 2x + 6 = 24

(8 + 6) - 2x = 24

14 - 2x = 24       <em>subtract 14 from both sides</em>

-2x = 10       <em>divide both sides by (-2)</em>

<h3>x = -5</h3>
4 0
3 years ago
Read 2 more answers
True or false: “If a positive integer is divisible by both 2 and 3, then it is divisible by 12.”
Julli [10]
False because 6 is divisible by 2 and 3, but not 12
4 0
2 years ago
Solve 4(x + 2) = 20
KiRa [710]

Answer:

x = 3

Explanation:

\sf 4(x + 2) = 20

\sf 4x + 8 = 20

\sf 4x = 20 - 8

\sf 4x = 12

\sf x = \frac{12}{4}

\sf x = 3

check:

4(x + 2) = 20

4(3 + 2) = 20

4(5) = 20

20 = 20

Hence proved x = 3

4 0
1 year ago
Read 2 more answers
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