All categories

3 years ago

Consider the scale drawing and actual drawing of an office.

Mathematics

2 answers:

iren2701 [21]3 years ago

8 0

Answer:

The scale factor is

✔ 2

The area of the scale drawing is

✔ 3.75 square inches

To find the area of the actual drawing, multiply the area of the scale drawing by the

✔ square

of the scale factor.

Step-by-step explanation:

Ymorist [56]3 years ago

3 0

Answer:

The scale factor is

✔ 2

The area of the scale drawing is

✔ 3.75 square inches

To find the area of the actual drawing, multiply the area of the scale drawing by the

✔ square

of the scale factor.

Step-by-step explanation:

You might be interested in

PLEASE HELP I'M TIMED

DedPeter [7]

Really hope i'm right

1st row

the first one is length less than 10

one next to it is width greater than 5

next to that is length greater than 10

2nd row

the first one is length greater than 10

one next to that is width less than 5

next to that is width greater than 5

3rd row

first one is width less than 5

and last is length less than 10

4 0

3 years ago

the length of a rectangular garden is one foot les than five times it's width. the area is 18 square feet find de width and leng

Harlamova29_29 [7]

The width is 2 and the length is 9 because 9 times 2 is 18 and 2 times 5 is 10. 10 minus 1 is 9 which then again 9 times 2 is 18 which is the area.

7 0

3 years ago

The figure below is a diagram of a trapezoidal table that needs to be stained. Each can of stain will cover 50 square inches.

Soloha48 [4]

Each can of stain covers 50 square inches.

Hence, we need 7 cans of stain to cover at least 324 square inches.

6 0

3 years ago

Help please for brainliest

kotegsom [21]

Answer:

Step-by-step explanation:

484848484848484848

3 0

4 years ago

Read 2 more answers

BRAINLIEST ASAP! PLEASE HELP ME :)

Margaret [11]

Answer:

$\large \boxed{\text{3.0 mi/h}}$

Step-by-step explanation:

Let x = the current of the river

Then 21 + x = the speed going downstream (with the current)

a nd 21 - x = the speed going upstream (against the current)

Distance = speed × time

d = st

t = d/s

Time going downstream = time going upstream

$\begin{array}{rcll}\dfrac{2.4}{21+ x}& = & \dfrac{1.8}{21 - x} &\\\\2.4& = &(21 + x) \dfrac{1.8}{21 - x} &\text{Multiplied each side by (21 + x)}\\\\2.4(21 - x)& = & 1.8(21 + x) &\text{Multiplied each side by (21 - x)}\\50.4 - 2.4x&=& 37.8 + 1.8x&\text{Removed parentheses}\\50.4 & = & 37.8 + 4.2x & \text{Added 2.4x to each side}\\\end{array}\\$

$\begin{array}{rcll}12.6 & = & 4.2x & \text{Subtracted 37.8 from each side}\\x & = &\dfrac{12.6}{4.2}&\text{Divided each side by 4.2}\\\\ & = &\mathbf{3.0}& \text{Simplified}\\\\\end{array}\\\text{The current is $\large \boxed{\textbf{3.0 mi/h}}$}$

Check:

$\begin{array}{rcl}\dfrac{2.4}{21+ 3}& = & \dfrac{1.8}{21 - 3}\\\\\dfrac{2.4}{24}& = & \dfrac{1.8}{18}\\\\0.10 & = & 0.10\\\end{array}$

4 0

3 years ago