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3 years ago

What is the range of the function?

Mathematics

1 answer:

levacccp [35]3 years ago

5 0

The answer is D. {-2, 2, 3, 4}

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In circle D, ∠EDH ≅ ∠EDG.

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Step-by-step explanation:

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4 years ago

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A lamppost, CAB, bent at point A after a storm. The tip of the lamppost touched the ground at point C, as shown below:

liubo4ka [24]

B) 14 tan 60 degrees

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3 years ago

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How do you find the sum of all integers between square root of 12 + square root of 40?

Mashutka [201]

3 < sqrt(12) < 4
6 < sqrt(40) < 7
So the only integers between those square roots are 5 and 6
Add them together.

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4 years ago

rodikova [14]

The answer is in the picture I’ll send u a link here phs.dcsdk12.org the answer is in there good luck!

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3 years ago

Write an equation of the line that passes through the given point and is (a) parallel and (b) perpendicular to the given line.

Harrizon [31]

Answer:

Equation of the line that passes through the given point and is (a) parallel is: $\mathbf{y=-2x+11}$

Equation of the line that passes through the given point and is (b) perpendicular is: $\mathbf{y=\frac{1}{2}x+1}$

Step-by-step explanation:

We need to Write an equation of the line that passes through the given point and is (a) parallel and (b) perpendicular to the given line.

First we will find slope of the line given in graph

The slope can be found using formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$

We have points (1,6) and (2,2)

Slope is:

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{2-6}{2-1}\\Slope=\frac{-4}{2}\\Slope=-2$

Part a)

Write an equation of the line that passes through the given point and is (a) parallel

When the lines are parallel, they have same slope. So, slope of required line: m = -2

Using slope m =-2 and point(4,3) we can find y-intercept b

$y=mx+b\\3=-2(4)+b\\3=-8+b\\b=3+8\\b=11$

The equation of line will be:

$y=mx+b\\y=-2x+11$

Equation of the line that passes through the given point and is (a) parallel is: $\mathbf{y=-2x+11}$

Part b)

Write an equation of the line that passes through the given point and is (b) perpendicular

When the lines are perpendicular they have opposite slope. So, slope of required line: m = 1/2

Using slope m =1/2 and point(4,3) we can find y-intercept b

$y=mx+b\\3=\frac{1}{2}(4)+b\\3=2+b\\b=3-2\\b=1$

The equation of line will be:

$y=mx+b\\y=\frac{1}{2}x+1$

Equation of the line that passes through the given point and is (b) perpendicular is: $\mathbf{y=\frac{1}{2}x+1}$

6 0

3 years ago