30 students.
5 + 2 + 4 + 7 + 5 + 9 = 32 students
<span>192 students. 32 students</span> = 6
so,
7 − 2 = 5
5 students × 6 = 30 students
The slope of the line is 1x. The slope shows that the more minutes she runs, the more calories she shows. It is also a positive slope.
Answer:
Each bouquet included 2 foil balloons and 8 latex balloons.
Step-by-step explanation:
Let f represent the number of foil balloons in each bouquet. Then 10-f is the number of latex balloons. The problem statement tells us the cost of all of the bouquets is ...
18(1.94f +0.17(10-f)) = 94.32
We can divide by 18 to get ...
1.94f +1.70 -0.17f = 5.24
1.77f = 3.54 . . . . . . . . . . . . subtract 1.70
f = 3.54/1.77 = 2 . . . . . . . . divide by the coefficient of f
The number of latex balloons is 10-2 = 8.
Each bouquet included 2 foil and 8 latex balloons.
Answer:
The coordinates of the ordered pair of the Image X' are: X'(-6, -1)
Step-by-step explanation:
When a point A(x, y) is rotated 90° counterclockwise around the origin, we flip x and y and reverse the sign of y.
Thus,
The rule to rotate a point A(x, y) after a rotation 90° counterclockwise around the origin is:
A(x, y) → A'(-y, x)
In our case, the point X (-1, 6) is rotated 90° counterclockwise about the origin. Thus, the coordinates of P' will be:
A(x, y) → A'(-y, x)
X (-1, 6) → X'(-6, -1)
Therefore, coordinates of the ordered pair of the Image X' are: X'(-6, -1)
X° +110° = 180* . . . . . "linear" angles
x = 70
x° +112° +y* +88° = 360° . . . . . sum of interior angles of a quadrilateral
y° +270° = 360°
y = 90
The values of the variables are
.. x = 70
.. y = 90
