Answer:
![x=\pm\sqrt{y+64}](https://tex.z-dn.net/?f=x%3D%5Cpm%5Csqrt%7By%2B64%7D)
Step-by-step explanation:
All you need to do is isolate the x.
First, add 64 to both sides:
![y=x^2-64\\x^2-64+64=y+64\\x^2=y+64](https://tex.z-dn.net/?f=y%3Dx%5E2-64%5C%5Cx%5E2-64%2B64%3Dy%2B64%5C%5Cx%5E2%3Dy%2B64)
Then, take the square root of both sides:
![\sqrt{x^2}=\sqrt{y+64}\\x=\sqrt{y+64](https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E2%7D%3D%5Csqrt%7By%2B64%7D%5C%5Cx%3D%5Csqrt%7By%2B64)
Actually, that is:
![x=\pm\sqrt{y+64}](https://tex.z-dn.net/?f=x%3D%5Cpm%5Csqrt%7By%2B64%7D)
Here's the reason for that. An example would be:
![x^2=4](https://tex.z-dn.net/?f=x%5E2%3D4)
Here, you'd take the square root of both sides to solve for x.
![\sqrt{x^2}=\sqrt{4}\\x=2](https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E2%7D%3D%5Csqrt%7B4%7D%5C%5Cx%3D2)
Right? But X could also be a -2, because a negative times a negative is a positive.
![(-2)^2=4\\-2\times-2=4\\4=4](https://tex.z-dn.net/?f=%28-2%29%5E2%3D4%5C%5C-2%5Ctimes-2%3D4%5C%5C4%3D4)
Therefore,
or ![x=\pm2](https://tex.z-dn.net/?f=x%3D%5Cpm2)
![x^2=2\times2=4\\x^2=-2\times-2=4](https://tex.z-dn.net/?f=x%5E2%3D2%5Ctimes2%3D4%5C%5Cx%5E2%3D-2%5Ctimes-2%3D4)
Answer:
5/y^3
Step-by-step explanation:
Answer:
Most precise to least precise
- Finding the height of the sun in the sky
- Counting heartbeats
- A calendar
- A stop watch
I am pretty sure it’s b!!