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Soloha48 [4]
3 years ago
15

I'm in a test please help

Mathematics
1 answer:
Margaret [11]3 years ago
8 0

Select ALL the correct answers. A bicycle manufacturer uses the given expression to model the monthly profit from sales of a new model of bicycle, where x is the selling price of one bicycle, in dollars. -12 + 3001 20,000 At what selling prices for the bicycle will the manufacturer make neither a profit nor a loss? $50

answer 250

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Max makes and sells posters. The function p(x)= -10x^2 +200x -250, graphed below, indicates how much profit he makes in a month
viktelen [127]
Here is our profit as a function of # of posters
p(x) =-10x² + 200x - 250
Here is our price per poster, as a function of the # of posters:
pr(x) = 20 - x
Since we want to find the optimum price and # of posters, let's plug our price function into our profit function, to find the optimum x, and then use that to find the optimum price:
p(x) = -10 (20-x)² + 200 (20 - x) - 250
p(x) = -10 (400 -40x + x²) + 4000 - 200x - 250
Take a look at our profit function. It is a normal trinomial square, with a negative sign on the squared term. This means the curve is a downward facing parabola, so our profit maximum will be the top of the curve.
By taking the derivative, we can find where p'(x) = 0 (where the slope of p(x) equals 0), to see where the top of profit function is.
p(x) = -4000 +400x -10x² + 4000 -200x -250
p'(x) = 400 - 20x -200
0 = 200 - 20x
20x = 200
x = 10                         
p'(x) = 0 at x=10. This is the peak of our profit function. To find the price per poster, plug x=10 into our price function:
price = 20 - x
price = 10
Now plug x=10 into our original profit function in order to find our maximum profit:
<span>p(x)= -10x^2 +200x -250
p(x) = -10 (10)</span>² +200 (10) - 250
<span>p(x) = -1000 + 2000 - 250
p(x) = 750

Correct answer is C)
</span>
7 0
3 years ago
(please zoom / zoom out if needed to see question. (: )
DaniilM [7]
Arc length = 2 π R (C/360)
where:
C  is the central angle of the arc
R  is the radius of the arc

arc length = 2 π R (137/360) = 2.39R
5 0
3 years ago
Karl is putting a frame around a rectangular photograph. The photograph is 14 inches long and 10 inches wide, and the frame is t
Sergeu [11.5K]
<h2>The area of the framed photograph = 1156 inch^{2}</h2>

Step-by-step explanation:

Given,

The length of photograph (l) = 14 inches and

The breadth of photograph (b) = 10 inches

To find, the area of the framed photograph = ?

We know that,

The area of the framed photograph = (l + 2b)(l + 2b)

= (14 + 2 × 10) (14 + 2 × 10) inch^{2}

= (14 + 20) (14 + 20) inch^{2}

= (34) (34) inch^{2}

= 1156 inch^{2}

∴ The area of the framed photograph = 1156 inch^{2}

8 0
3 years ago
Which ratio is not equivalent to -(1/3) (#6)
LuckyWell [14K]

Answer:

answer b

Step-by-step explanation:

hope that helps

7 0
2 years ago
A picture frame can hold a photograph that is 16 inches long and 12 inches wide.
Mila [183]

Answer:

192 inches because 16×12=192

8 0
3 years ago
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