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3 years ago

I'm in a test please help

1 answer:

8 0

Select ALL the correct answers. A bicycle manufacturer uses the given expression to model the monthly profit from sales of a new model of bicycle, where x is the selling price of one bicycle, in dollars. -12 + 3001 20,000 At what selling prices for the bicycle will the manufacturer make neither a profit nor a loss? $50

answer 250

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In the triangle shown, B=60 and AC=9√3 how long is AB answer exactly, use a radical if needed

zavuch27 [327]

Length of AB is 18

Step-by-step explanation:

Step 1: Find length of AB when AC = 9√3 and ∠B = 60°. Use trigonometric ratio sine.

sin 60 = opposite side/hypotenuse = 9√3/x

x = 9√3/sin 60

= 9√3/√3/2 = 9√3 × 2/√3 (∵ a ÷ b = a×1/b)

= 18

5 0

3 years ago

898÷91,596 what is the answer

Dmitrij [34]

Answer:

For 100, your answer will be 102; For 898, your answer will be x; 100*x = 102*898 ... 102/x = 100/898 or x/102 = 898/100; x = 898*102/100 = 91596/100 = 915.96.

Hope this helps ∝

∅¬∅

7 0

3 years ago

Read 2 more answers

What is the length of the shadow cast by a 12-foot lamp post when the angle of elevation of the sun is 60º? (to the nearest tent

elena-s [515]

Answer:

6.9 foot.

Step-by-step explanation:

Given: Length of lamp post= 12-foot.

The angle of elevation of the sun is 60°.

∴ The length of Lamp post, which is opposite is 12-foot.

Now, finding the length of shadow cast by foot lamp.

Length of shadow is adjacent.

∴ We know the formula for $Tan\theta$ = $\frac{Opposite}{adjacent}$

Next, putting the value in the formula.

⇒ $Tan 60° = \frac{12}{adjacent}$

Cross multiplying both side and using the value of Tan 60°

∴ Adjacent= $\frac{12}{\sqrt{3} } = 6.92$ ≅ 6.9 (nearest tenth value)

6.9 is the length of shadow cast by a 12-foot lamp post.

3 0

3 years ago

Find the area of the rhombus

MAXImum [283]

<h3> Solution :-</h3>

Area of rhombus :-

$\bf \star \: \: \boxed{ \bf \dfrac{d_{1}d_{2}}{2} }$

$\sf \longrightarrow d_{1} = 4 \sqrt{3} + 4 \sqrt{3} = 8 \sqrt{3}$

$\sf \longrightarrow d_{2} = 4 + 4 = 8$

Area of rhombus :-

$: \implies \sf \dfrac{8 \sqrt{3} \times 8 }{2}$

$: \implies \sf 8 \sqrt{3} \times 4$

$: \implies \bf 32 \sqrt{3} \: {m}^{2}$

6 0

3 years ago

(m^-4/3)^1/4 divided by m^0 n^3/4(m^-3/2 n^2)

postnew [5]

$\frac{(m^{-\frac{4}{3}})^{\frac{1}{4}}}{m^{0}(m^{-\frac{3}{2}}n^{2})} = \frac{m^{-\frac{1}{3}}}{m^{-\frac{3}{2}}n^{2}} = \frac{m^{\frac{3}{2}}}{m^{\frac{1}{3}}n^{2}} = \frac{m^{\frac{7}{6}}}{n^{2}} = \frac{\sqrt[6]{m^{7}}}{n^{2}} = \frac{\sqrt[6]{m^{6} * m}}{n^{2}} = \frac{\sqrt[6]{m^{6}}\sqrt[6]{m}}{n^{2}} = \frac{m\sqrt[6]{m}}{n^{2}}$

6 0

3 years ago