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Soloha48 [4]
3 years ago
15

I'm in a test please help

Mathematics
1 answer:
Margaret [11]3 years ago
8 0

Select ALL the correct answers. A bicycle manufacturer uses the given expression to model the monthly profit from sales of a new model of bicycle, where x is the selling price of one bicycle, in dollars. -12 + 3001 20,000 At what selling prices for the bicycle will the manufacturer make neither a profit nor a loss? $50

answer 250

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PLEASE HELP 50 POINTS
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Answer:

im leaning on parallelogram

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Whats the answer for 2x + 1 + 7x ?
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Answer:

9x+1

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combine 2x+7x then add the 1

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Guy what 5x4 please help me
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20

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Jeremy is taking a photography class, but he doesn't own a camera. The class organizers will rent him a camera for $6 per day. J
Mazyrski [523]
Solving the given inequality for d, we get...

6d + 15 < 50
6d + 15-15 < 50-15 <<-- subtract 15 from both sides
6d < 35
6d/6 < 35/6 <<--- divide both sides by 6
d < 5.83

Which means that d can be any of the values in this set: {0, 1, 2, 3, 4, 5}

The smallest d can be is 0. In this scenario, Jeremy pays the $15 registration but doesn't rent the camera at all
The largest d can be is 5. In this scenario, Jeremy rents the camera for 5 days
Any larger value of d is not allowed as it would make the total cost go over $50
Notice how I'm rounding down regardless how close 5.83 is to 6

8 0
3 years ago
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Determine the rational zeros for the function f(x)=x^3+7x^2+7x-15
alexandr402 [8]

Answer:

1,-3,-5

Step-by-step explanation:

Given:

f(x)=x^3+7x^2+7x-15

Finding all the possible rational zeros of f(x)

p= ±1,±3,±5,±15 (factors of coefficient of last term)

q=±1(factors of coefficient of leading term)

p/q=±1,±3,±5,±15

Now finding the rational zeros using rational root theorem

f(p/q)

f(1)=1+7+7-15

   =0

f(-1)= -1 +7-7-15

     = -16

f(3)=27+7(9)+21-15

    =96

f(-3)= (-3)^3+7(-3)^2+7(-3)-15

     = 0

f(5)=5^3+7(5)^2+7(5)-15

    =320

f(-5)=(-5)^3+7(-5)^2+7(-5)-15

      =0    

f(15)=(15)^3+7(15)^2+7(15)-15

     =5040

f(-15)=(-15)^3+7(-15)^2+7(-15)-15

      =-1920

Hence the rational roots are 1,-3,-5 !

4 0
3 years ago
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