Answer:
P(x) = x + 2
Piden: A = P(P(P(P(3))))
P(3); x = 3
P(3) = 3 + 2 = 5
A = P(P(P(P(3))))
A = P(P(P(5)))
P(5); x = 5
P(5) = 5 + 2 = 7
A = P(P(P(5)))
A = P(P(7))
P(7); x = 7
P(7) = 7 + 2 = 9
A = P(P(7))
A = P(9)
P(9); x = 9
P(9) = 9 + 2 = 11
→ A = P(P(P(P(3)))) = 11
Step-by-step explanation:
listo e
Answer:
6
Step-by-step explanation:
Plug in 3 into both expressions
Then add those results
2(3)+21=6+21=27
3-24 =-21
-------
6 is the sum of 27 and -21
First write an equation system based on the problem
We can write "<span>Bread and sugar cost 110 together" as
</span>∴ b + s = 110
We can write "<span>bread cost 100 more than sugar" as
</span>∴ b = 100 + s
<span>
Second, solve the equation system by subtitution method
Subtitute b with (100+s) in the first equation, and we'll find the value of s
b + s = 110
(100 + s) + s = 110
100 + 2s = 110
2s = 110 - 100
2s = 10
s = 10/2
s = 5
The cost of the sugar is 5</span>
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
