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3 years ago

Find, from first principles,the derivative of e^tanx

Mathematics

1 answer:

Anettt [7]3 years ago

6 0

Answer:

[(sec^2)(x)]. [e^tan(x)]

[e^(tan(x))]/[(cos^2)(x)].

Step-by-step explanation:

d/dx(e^tan(x))

From the low:

[(d/du)(e^u)]=[(d/du)(u)]. [ln(e)]. [e^u]

=[(sec^2)(x)]. [e^(tan(x))]. [ln(e)]

=[(sec^2)(x)]. [e^(tan(x))]

[e^(tan(x))]/[(cos^2)(x)].

Because

(cos^2)(x)=1 / (sec^2)(x)

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Robert and Chris can skate 4 miles in 18 minutes. How far can they ride in 45 minutes?

adell [148]

Answer: Robert and Chris can skate 10 miles in 45 minutes.

Step-by-step explanation:

Let's start by finding the unit rate.

$\frac{4}{18} =\frac{2}{9} \\\frac{18}{18} =1$

Robert and Chris can skate $\frac{2}{9}$ of a mile in 1 minute. Now we can multiply both by 45 to see how far the can go in 45 minutes.

$(\frac{2}{9}) (\frac{45}{1} )\\\frac{(2)(45)}{(9)(1)} \\\frac{90}{9} \\10$

45x1=45

The can skate 10 miles in 45 minutes.

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3 years ago

For a brainlist +10 points please help

Strike441 [17]

Answer:

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Explanation:

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2 years ago

A concrete mix is designed to withstand 3000 pounds per square inch (psi) of pressure. The following data represent the strengt

ss7ja [257]

Answer:

Mean = 3640

Mode = 4100

Median = 3830.

Step-by-step explanation:

We are given the following data in the question:

Strength of casts (in psi):

3970,4100,3100,3200,2950,3830,4100,4050,3460

Formula:

$Mean = \displaystyle\frac{\text{Sum of all observation}}{\text{Total number of observations}}$

$\displaystyle\frac{3970+4100+3100+ 3200+ 2950+ 3830+4100+ 4050+ 3460}{9} = \displaystyle\frac{32760} {9} = 3640$

Mode is the entry with most frequency. Thus, for the given sample mode = 4100.

Median

Since n = 9 is odd,

Formula:

$Median = \displaystyle\frac{n+1}{2}th~term$

Data in ascending order:

2950,3100,3200,3460,3830,3970,4050,4100,4100

Median = 5th term = 3830.

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3 years ago

There is a large number of cubes in a bag.

Alla [95]

Marked(10)/total = 3/20 (from sample)

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total = 10•20/3 = 200/3 ≈ 67

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3 years ago

An internet service provider changes an initial fee of $65 and $18 per hour of labor for office internet installation. Which equ

OlgaM077 [116]

<h2>Answer:</h2><h2>The total cost (C) charged by the internet service provider = $65 + $18(n)</h2>

Step-by-step explanation:

Initial fee charged by the servic eprovider = $65

Cost per hour of labor for office internet installation = $18

The cost per hour be $18

Cost per two hours = 18 * 2 = $36

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where h represents the number of hours

The total cost (C) charged by the internet service provider = $65 + $18(n)

5 0

3 years ago

Find, from first principles,the derivative of e^tanx​

Find, from first principles,the derivative of e^tanx