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Sergeu [11.5K]
2 years ago
10

SOMEONE HELPPP PLEASE!! Complete the table to represent the number of seashells in the collection after the first four summers

Mathematics
1 answer:
Mice21 [21]2 years ago
4 0

Answer:

6 number of seashells for 1 Summer. 21 number of seashells for two summers. 36 number of seashells for three summers. 51 number of seashells for 4 summers.

Step-by-step explanation:

15 substituted in for f and x is the the number of summers.

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Find the distance between A (2.6) and N (5,10). Round to the nearest tenth, if necessary.
Triss [41]

Answer:

5

Step-by-step explanation:

6 0
3 years ago
What is the question of the line that passes through the point (-2,-2) and has a slope of 4. Plz someone answer
Studentka2010 [4]

Answer:y=4x+6

Step-by-step explanation:

We have the information that the slope is 4 and the line goes through the point (-2,-2). With this information, we can make a linear equation in a point slope form (y - y_{1}= m * (x - x_{1}), so the equation would be y+2=4(x+2), or simplified, y+2=4x+8. in order to solve for y (to make it a slope-intercept equation), we must subtract 2 from both sides. This gives us the equation y=4x+6. Hope this helps!

4 0
3 years ago
A box with a square base and open top must have a volume of 32,000 cm3. find the dimensions of the box that mini- mize the amoun
zmey [24]
Alrighty


squaer base so length=width, nice


v=lwh
but in this case, l=w, so replace l with w
V=w²h

and volume is 32000
32000=w²h


the amount of materials is the surface area
note that there is no top
so
SA=LW+2H(L+W)
L=W so
SA=W²+2H(2W)
SA=W²+4HW

alrighty

we gots
SA=W²+4HW and
32000=W²H

we want to minimize the square foottage
get rid of one of the variables
32000=W²H
solve for H
32000/W²=H
subsitute

SA=W²+4WH
SA=W²+4W(32000/W²)
SA=W²+128000/W

take derivitive to find the minimum
dSA/dW=2W-128000/W²
where does it equal 0?

0=2W-1280000/W²
128000/W²=2W
128000=2W³
64000=W³
40=W

so sub back
32000/W²=H
32000/(40)²=H
32000/(1600)=H
20=H

the box is 20cm height and the width and length are 40cm
7 0
3 years ago
Alyssa takes part in the triathlon. She cycles 4/5 of the route, runs 7/8 of the route, and swims the rest of the way. She swims
hjlf

Answer:

12 miles

Step-by-step explanation:

Alyssa takes part in the triathlon. She cycles 4/5 of the route, runs 1/8 of the route, and swims the rest of the way. She swims 0.9 miles. Find the total distance of the triathlon route.

Total distance Alyssa cycled and ran =

\frac{4}{5} + \frac{1}{8}

\frac{32 + 5}{40} = \frac{37}{40}

Distance she swam =  1 - 37/40 = 3/40

3/40 of the distance is 0.9

the total distance = 40/3 x 0.9 = 12 miles

3 0
2 years ago
Factor completely: 2x3 + 6x2 + 10x + 30
qwelly [4]
The complete factor from:

2x3 + 6x2 + 10x + 30
2x(x+3) + 10(x+3)
(x+3)(2x+10)
2(x+5)(x+3)

hope this help
3 0
3 years ago
Read 2 more answers
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