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melisa1 [442]
3 years ago
10

Find the area of the triangle. 294 m2 367.5 m2 490 m2 980 m2

Mathematics
1 answer:
geniusboy [140]3 years ago
4 0

Answer:

294 m2

Step-by-step explanation:

\frac{hxb} 2 so therefore \frac{28x21}{2} = 294

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A right rectangular prism has a base with sides 6 cm and 8 cm. If the volume of the prism is 624 cm^3, find the height of the pr
nika2105 [10]

Answer:

H=13cm

Step-by-step explanation:

Volume= Length x Width x Height

v=624cm^3

L=8cm

W=6cm

8cm x 6cm=48cm^2

Divide 624cm^3 by 48cm^2= 13cm

H=13cm

Hope this helps!

8 0
3 years ago
A rain storm came through Clifton park and it was accumulating 2/3 inches of rain/hour. How many inches of rain would fall in 6
nlexa [21]

4 inches of rain would fall in 6 hours

<h3><u>Solution:</u></h3>

Given that, A rain storm came through Clifton park  

And it was accumulating \frac{2}{3} inches of rain/hour

So amount of rain accumulated in 1 hour = \frac{2}{3}

Thus amount of rain accumulated in six hours is calculated by multiplying the amount of water accumulating per hour and 6

Amount of water accumulated in 6 hours = Amount of water accumulated in 1 hour \times 6

\text { Amount of water accumaulated in 6 hours }=\frac{2}{3} \times 6=4

<em><u>Another way:</u></em>

Let "n" be the amount of rain accumulated in 6 hours

1 hour ⇒ \frac{2}{3} rain accumulated

6 hours ⇒ "n"

By cross multiplication, we get

6 \times \frac{2}{3} = 1 \times n\\\\n = \frac{2}{3} \times 6 = 4

Hence, 4 inches of rain would fall in 6 hours.

4 0
3 years ago
the male elephant at the city zoo weigh 8,000 pound, which is the same as 4 tons. the female elephant weigh 7,000 pounds. how ma
zvonat [6]

Answer:

3.5 tons

Step-by-step explanation:

Divide the pounds for the male by the amount of tons it is.

8000/4 = 2000

This is how many pounds are in one ton.  Divide the weight of the female by this.

7000/2000 = 3.5

The female weighs 3.5 tons.

6 0
3 years ago
Help it’s for algebra 1
Masja [62]
F(2) = -5(2) + 7
f(2) = -10 + 7
f(2) = -3
4 0
3 years ago
The data represent the results for a test for a certain disease. Assume one individual from the group is randomly selected. Find
sertanlavr [38]

Answer:

The probability of getting someone who tests positive​, given that he or she had the disease is 0.8954.

Step-by-step explanation:

The data provided is:

                  YES        NO    Total

Positive      137           8      145

Negative     16          139    155

Total            153         147    300

An individual is selected at random from the group.

We need to compute the probability of getting someone who tests positive​, given that he or she had the disease.

The conditional probability of an event <em>A</em> given that another event <em>B</em> has already occurred is:

P(A|B)=\frac{P(A\cap B)}{P(B)}=\frac{n(A\cap B)}{n(B)}

Let <em>A</em> = individuals who tests positive and <em>B</em> = individual who had the disease.

The number of individuals who tests positive and had the disease is,

n (A ∩ B) = 137

n (B) = 153

Compute the conditional probability of A given B as follows:

P(A|B)=\frac{n(A\cap B)}{n(B)}

            =\frac{137}{153}

            =0.8954

Thus, the probability of getting someone who tests positive​, given that he or she had the disease is 0.8954.

8 0
3 years ago
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