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Dennis_Churaev [7]
3 years ago
14

_________________ please help!!!!!!!

Mathematics
1 answer:
jeka943 years ago
5 0

Answer:

The answer would be C)5

Step-by-step explanation:

The unknown triangle is half of the size of the original triangle, The right side measurement basically hints to the actual answer.

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Answer:

shell pay morethen 30

Step-by-step explanation:

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3 years ago
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A rocket launches upward off of a 18 ft platform with an initial velocity of 125 ft/sec creating the equation begin mathsize 18p
Dmitry_Shevchenko [17]
Um i this is not my level
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3 years ago
At a raffle, 1500 tickets are sold at $2 each. There are four prizes given for $500, $250, $150, and $75. You buy one ticket. Us
wolverine [178]

Answer:

<u>The expected value of every ticket is a loss of $ 1.35</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Number of tickets sold at the raffle = 1,500

Price of each ticket = $ 2

Total prizes = 1 * $ 500 + 1 * $ 250 + 1 * $ 150 + 1 * $ 75

2. Use a probability distribution table to calculate the expected value of your gain. Your expected value is_____ ?

Let's answer the question using a probability distribution for the gains, this way:

  • Probability of 1st prize of $ 498 (500 - ticket) = 1/1,500
  • Probability of 2nd prize of $ 248 (250 - ticket) = 1/1,500
  • Probability of 3rd prize of $ 148 (150 - ticket) = 1/1,500
  • Probability of 4th prize of $ 73 (75 - ticket) = 1/1,500
  • Probability of losing $ 2 (ticket) = 1,496/1,500

Now, we calculate the mean for all the tickets (winners and non-winners), this way:

Expected value = [(1,496 * -2) + (1 * 498) + (1 * 248) + ( 1 * 148) + ( 1 * 73)]/1,500

Expected value = [- 2,992 +498 + 248 + 148 + 73)/1,500

Expected value = -2,025/1,500 = - 1,35

<u>The expected value of every ticket is a loss of $ 1.35</u>

8 0
4 years ago
1(2.5.3)(2.4.8)(6.2.9.4)
skelet666 [1.2K]
Explain further? Thanks....
6 0
3 years ago
a(t) = (t - k)(t - 3)(t - 6)(t + 3) is a polynomial function of t, where k is a constant. Given that a(2) = 0, what is the absol
koban [17]
If a(2) = 0, then k=2. The product of the zeros is
(2)*(3)*(6)*(-3) = -108

The absolute value of the product of zeros of a(t) is 108.
4 0
3 years ago
Read 2 more answers
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